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kenny6666 [7]
3 years ago
8

Use the E0 values of the following elements: Zn, Cu, Pb, and Al.

Chemistry
2 answers:
Radda [10]3 years ago
8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

E_o values are known as standard reduction potential values. More the positive reduction potential values, the metal will easily gain electron and will undergo reduction reaction easily.

The standard reduction potential values of the given metals are:

E_O_{(Zn)}=-0.7618V\\E_O_{(Cu)}=0.337V\\E_O_{(Pb)}=-0.126V\\E_O_{(Al)}=-1.662V

Copper has positive reduction potential than lead and thus, will undergo reduction reaction easily. It will gain electrons from other substance. So, the other substance will easily loose electrons and it will therefore oxidize.

Hence, the correct answer is Option B.

Sophie [7]3 years ago
3 0

B is the correct answer

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how many grams of fertilizer , for potassium sulfate are there in 42.3 mole of potassium sulfate? step by step
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Answer:

The mass of 42.3 moles of potassium sulfate is 7,371.1557 grams

Explanation:

Potassium sulfate K₂SO₄ which is also known as sulphate of potash is a water soluble common component of fertilizer

The molar mass of potassium sulfate, M = 174.259 g/mol

The given number of moles of potassium sulfate, n = 42.3 moles

The mass, 'm', of a given number of moles of potassium sulfate, 'n', is given as follows;

m = n × M

Therefore, we have;

The mass, 'm', of 42.3 moles of potassium sulfate is found by plugging in the values for 'M', and 'n', in the above equation as follows;

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4 0
3 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

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For hydrogen, H:

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For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

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Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

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H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

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