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umka2103 [35]
3 years ago
6

When the water inside a living cell freezes, the ice crystals damage the cell. The wood frog is a unique creature that can survi

ve being frozen. In extremely cold
conditions, the frogs liver produces large amounts of glucose (C6H12O6), which becomes concentrated in the frog's cells. How does the glucose help prevent ice

from forming in the frogs cells?

A)The added glucose dissociates and creates faster moving molecules.

B) The added glucose lowers the vapor pressure relative to the pure solvent.

C) The added glucose requires more energy which warms the frog

D)The added glucose lowers the freezing point of the solution within the frog's cells.
Chemistry
1 answer:
professor190 [17]3 years ago
4 0
But i think its B but i need answer too
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A sample of 250 g of water are heated from 40°C to 121°C, calculate the amount of heat energy absorbed.
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Answer:

the anwser isn't in the choices

Explanation:

H=MC(change of temp.)

M=mass of water=250g

C=specific heat of water = 4.186 j/g

change in temperature is 121-40= 81

H= 250x4.186x81=84766.5J

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Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
3 years ago
What is the molarity of a 2.0 liter solution containing 58 grams of nacl?
Savatey [412]
First, need to know the formula of Molarity. 
                     moles of solute
  Molarity = ---------------------------
                      liters of solution

Given 
    2.0 liter of solution 
    58 grams of NaCl

Base of my research the moles of 58 grams of NaCl is 0.750 moles

Solution

                    0.750 moles
Molarity = -----------------------              = 0.375
                             2.0 L

The molarity of this solution is 0.375 
 
4 0
3 years ago
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