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umka2103 [35]
3 years ago
6

When the water inside a living cell freezes, the ice crystals damage the cell. The wood frog is a unique creature that can survi

ve being frozen. In extremely cold
conditions, the frogs liver produces large amounts of glucose (C6H12O6), which becomes concentrated in the frog's cells. How does the glucose help prevent ice

from forming in the frogs cells?

A)The added glucose dissociates and creates faster moving molecules.

B) The added glucose lowers the vapor pressure relative to the pure solvent.

C) The added glucose requires more energy which warms the frog

D)The added glucose lowers the freezing point of the solution within the frog's cells.
Chemistry
1 answer:
professor190 [17]3 years ago
4 0
But i think its B but i need answer too
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3 years ago
Calculate the pH of a solution created by placing 2.0 grams of yttrium hydroxide, Y(OH)3, in 2.0 L of H2O. Ksp for Y(OH)3 is 6.0
oee [108]

Answer:

pH = 8.314

Explanation:

  • Y(OH)3(s) ↔ Y+  +  3OH-

equil:   S               S         3S

∴ Ksp = [ Y+ ] * [ OH- ]³ = 6.0 E-24

⇒ 6.0 E-24 = ( S )*( 3S )³

⇒ 6.0 E-24 = 27S∧4

⇒ 2.22 E-25 = S∧4

⇒ ( 2.22 E-25 )∧(1/4) = S

⇒ S = 6.866 E-7 M

⇒ [ OH- ] = 3*S =2.06 E-6 M

⇒ pOH = - Log [ OH- ]

⇒ pOH = - Log ( 2.06 E-6 )

⇒ pOH = 5.686

∴ pH = 14 - pOH

⇒ pH = 8.314

8 0
3 years ago
HELP!! BEST ANSWER GETS BRAINLIEST!!
vampirchik [111]
<span> The anwser is D. Radiation, because it can travel thru air.</span>
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3 years ago
A chemist has some 40% acid solution, some 60% acid solution, and a wholebunch of free time. How many liters of each should be u
TiliK225 [7]

Answer:

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

Explanation:

Let volume of the 40% acid solution be x.

Let volume of the 60% acid solution be y.

Volume of solution formed after mixing both solution = 40 L

x + y = 40 L..[1]

Volume of acid 40% solution = 40% of x= 0.4x

Volume of acid 60% solution = 60% of y= 0.6y

Volume of acid formed = 45% of 40 L = \frac{45}{100}\times 40=18L

0.4x+0.6y=18 L..[2]

Solving [1] and [2]

x = 30 L  ,   y = 10 L

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

8 0
3 years ago
How many moles are in 8.2 x 10^22molecules of N2I6?
stiks02 [169]

Answer:

First, find out how many moles of N2I6 you have. Then convert that to grams.

molar mass N2I6 = 789 g

moles N2I6 = 8.2x1022 molecules N2I6 x 1 mole/6.02x1023 molecules = 1.36x10-1 moles = 0.136 moles

grams N2I6 = 0.136 moles x 789 g/mole = 107 g = 110 g (to 2 significant figures)

6 0
2 years ago
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