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timurjin [86]
4 years ago
6

When monochromatic light passes through the interface between two unknown materials at an angle θ where 0∘<θ<90∘, no chang

es in the direction of propagation of light are observed. What can be said about the two materials?
Physics
1 answer:
aliina [53]4 years ago
4 0

The question is incomplete, the options in the question are:

The two materials have matching indexes of refraction.

The second material through which light propagates has a lower index of refraction.

The second material through which light propagates has a higher index of refraction.

The two materials are identical

Answer:

The two materials have matching indexes of refraction.

Explanation:

The phenomenon of refraction reveals that, when light propagates through the interface between two materials with different indexes of refraction, the direction of propagation of light changes. When this does not happen, it means that the two materials have very similar refractive indexes. For instance, the refractive index of glass Pyrex is 1.474 and that of glycerin is 1.473 hence no relevant change in the direction of propagation of light can be observed when light passes between the interface of the two substances. That does not mean that they are both the same material or identical materials.

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f= 241/30=8.03Hz

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5 0
2 years ago
Read 2 more answers
11 e) Can a conductor be given limitless charge? Obtain the equivalent resistance of several resistors if (a) they are in series
horsena [70]

Answer:

(e) no

(a) Rs = R' + R'' + R'''

(b) 1/Rp = 1/R' + 1/R'' + 1/R'''

Explanation:

11 e)

Practically it is not possible to give limitless charge to a conductor. It depends to the number of valence electrons.

(a) When the three resistances R'. R'' and R''' is in series combination.

Let they are connected to the voltage V and the current in each resistance is I.

According to Ohm's law

Voltage across R', V' = I R'

Voltage across R'', V'' = I R''

Voltage across R''', V''' = I R'''

So, let the equivalent resistance is Rs.

I Rs = I R' + I R'' + I R'''

Rs = R' + R'' + R'''

(b)

When the three resistances R'. R'' and R''' is in parallel combination.

Let they are connected to the voltage V and the current in each resistance is I', I''. I'''.

Current in R', I' = V/R'

Current in R'', I'' = V/R''

Current in R''', I''' = V/R'''

The equivalent resistance is Rp.

V/Rp = V/R' + V/ R'' + V/R'''

1/Rp = 1/R' + 1/R'' + 1/R'''

6 0
3 years ago
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