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sdas [7]
3 years ago
15

Earth Science help needed

Physics
2 answers:
denis23 [38]3 years ago
6 0
D it is D the answer is D

Maurinko [17]3 years ago
5 0

Answer:

It is letter D. core, mantle crust

Explanation:

i got this from study island i got the same question

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A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
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Answer:

Explanation:

Surface charge density, σ = 9 μC/m² = 9 x 10^-6 C/m²

According to the Gauss theorem,

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A −4.00 μC charge sits in static equilibrium in the center of a conducting spherical shell that has an inner radius 3.13 cm and
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Answer:

(a). The charge on the outer surface is −2.43 μC.

(b). The charge on the inner surface is 4.00 μC.

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Explanation:

Given that,

Charge q₁ = -4.00 μC

Inner radius = 3.13 m

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Net charge q₂ = -6.43 μC

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Using formula of charge

q_{out}=q_{2}-q_{1}

q_{out}=-6.43-(-4.00)

q_{out}=-2.43\ \mu C

The charge on the inner surface is q.

q+(-2.43)=-6.43

q=-6.43+2.43= 4.00\ \mu C

We need to calculate the electric field outside the shell

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times6.43\times10^{-6}}{(4.13\times10^{-2})^2}

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E=3.39\times10^{7}\ N/C

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(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is 3.39\times10^{7}\ N/C

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