A tennis ball traveling horizontally at 22.0 m/s suddenly hits a vertical brick wall and bounces back with a horizontal velocity
1 answer:
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Answer:
422.36 N
Explanation:
given,
time of rotation = 4.30 s
T = 4.30 s
Assuming the diameter of the ring equal to 16 m
radius, R = 8 m
v = 11.69 m/s
now, Force does the ring push on her at the top
N = 422.36 N
The force exerted by the ring to push her is equal to 422.36 N.
Answer:
(a) 19.71801m/s Velocity just before going up the ramp.
(b) 74.56338m.
Explanation:
We will solve it in two parts, first we will calculate time that 5kg wooden block would take to just reach ramp and with this time we will calculate final velocity that the wooden block would have in this time.
Second, we will calculate the component of velocity vector along inclined plane and the time that it would take for velocity to be 0 meters/s then with this time we will calculate the distance that inclined plane would travel along inclined plane.
Following formulas will be used.
(a) Calculating velocity right before going up the ramp.
Wooden block is going on a straightaway and has net for on it.
=
and this force produces acceleration of
With this acceleration, wooden block would reach at the foot of ramp in.
and final velocity will be
this velocity of wooden box just before going up the ramp.
(b) How far up the ramp will the wooden block go before stopping.
Ramp is at 20° relative to horizontal therefore velocity along the ramp that the wooden block would have will be.
and deceleration along the ramp is
Where force of friction along the inclined plane.
is a component of g along normal of the inclined plane.
And with this deceleration time needed to get wooded block to stop is.
and in that time wooden block would travel
This is how up wooden box will go before coming to stop.
Answer:
Do neither of these things ( c )
Explanation:
For length contraction : Is calculated considering the observer moving at a speed that is relative the object at rest applying this formula
L = (l)
where l = Measured distance from object at rest, L = contracted measured in relation to the observer , v = speed of clock , c = speed of light
you will do neither of these things because before you can make such decisions who have to view the object in this case yourself from a different frame from where you are currently are, if not your length and width will not change hence you can't make such conclusions/decisions .
Answer:
Explanation:
We first identify the elements of this simple harmonic motion:
The amplitude A is 8.8cm, because it's the maximum distance the mass can go away from the equilibrium point. In meters, it is equivalent to 0.088m.
The angular frequency ω can be calculated with the formula:
Where k is the spring constant and m is the mass of the particle.
Now, since the spring starts stretched at its maximum, the appropriate function to use is the positive cosine in the equation of simple harmonic motion:
Finally, the equation of the motion of the system is:
or