The combined momentum of the passengers is 5000 kgm/s.
<h3>Combined momentum of the passenger</h3>
The combined momentum of the passengers is calculated as follows;
P = mv1 + mv2
where;
- m is mass of the passengers
- v1 is velocity of the first passenger
- v2 is velocity of the second passenger
P = m(v1 + v2)
P = 5000(-1 + 2)
P = 5000 kgm/s
Thus, the combined momentum of the passengers is 5000 kgm/s.
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C. combustion I think. hope this helps
Answer:
17.55 m/s²
Explanation:
Parameters given:
Mass of Krypton, M = 7.6 * 10^23 kg
Radius, R = 1.7 * 10^6 m
Gravitational constant, G = 6.6726 * 10^(-11) Nm²/kg²
Acceleration due to gravity of planet of mass M is given as:
g = GM/R²
Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.
Therefore,
g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²
g = 17.55 m/s²
'Ampere' is the unit of current. That's the rate at which
electrons travel in the circuit ... the number of electrons
every second. If you wanted the actual amount or number
of electrons, you'd need to know the length of time too.
It doesn't matter whether we're talking about a parallel or
series circuit.
