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scoray [572]
3 years ago
13

The light bulb transfers electrical energy into light. What is one type of energy that is also generated that is NOT a desired e

ffect?
A)
chemical
B)
heat
C)
mechanical
D)
sound
Physics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

B

Explanation:

heat

Troyanec [42]3 years ago
5 0

Light bulbs get hot !

The heat is not a desired effect, and the light bulb is not very efficient,
if you selected a light bulb to serve as a source of light.  But if chose a
light bulb to use in a place where you need heat, then the heat you get
from it is very desirable, and the light bulb is very efficient.  It all depends
on your point of view.
 
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All but two gaps within a set of Venetian blinds have been blocked off to create a double-slit system. These gaps are separated
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Answer:

Explanation:

separation between two gaps, d = 5 cm

angle between central and second order maxima, θ = 0.52°

use

d Sinθ = n λ

n = 2

0.05 x Sin 0.52° = 2 x λ

λ = 2.27 x 10^-4 m

λ = 226.9 micro metre

6 0
3 years ago
In the Compton effect, the wavelength of the scattered photon is __________ the wavelength of the incident photon.
SOVA2 [1]

Answer:

he wavelength is different (greater) than the wavelength of the incident photon

Explanation:

The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes

To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon

3 0
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An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above
Lilit [14]
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Given,

length of object, h_o = 3 cm

We know, for flat refracting surface,  

Image distance = object distance

So,

magnification is = -1

length of the image,

h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm

Here, negative sign means inverted image.

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3 0
3 years ago
Calculate the total distance traveled (in m)
nlexa [21]

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3 0
4 years ago
Read 2 more answers
A 95.0 kg satellite moves on a circular orbit around the Earth at the altitude h=1.20*103 km. Find: a) the gravitational force e
Natali5045456 [20]

Answer:

a) F = 660.576\,N, b) a_{c} = 6.953\,\frac{m}{s^{2}}, c) v \approx 7255.423\,\frac{m}{s}, \omega = 9.583\times 10^{-4}\,\frac{rad}{s}, d) T \approx 1.821\,h

Explanation:

a) The gravitational force exerted by the Earth on the satellite is:

F = G\cdot \frac{m\cdot M}{r^{2}}

F = \left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot \frac{(95\,kg)\cdot (5.972\times 10^{24}\,kg)}{(7.571\times 10^{6}\,m)^{2}}

F = 660.576\,N

b) The centripetal acceleration of the satellite is:

a_{c} = \frac{660.576\,N}{95\,kg}

a_{c} = 6.953\,\frac{m}{s^{2}}

c) The speed of the satellite is:

v = \sqrt{a_{c}\cdot R}

v = \sqrt{\left(6.953\,\frac{m}{s^{2}} \right)\cdot (7.571\times 10^{6}\,m)}

v \approx 7255.423\,\frac{m}{s}

Likewise, the angular speed is:

\omega = \frac{7255.423\,\frac{m}{s} }{7.571\times 10^{6}\,m}

\omega = 9.583\times 10^{-4}\,\frac{rad}{s}

d) The period of the satellite's rotation around the Earth is:

T = \frac{2\pi}{\left(9.583\times 10^{-4}\,\frac{rad}{s} \right)} \cdot \left(\frac{1\,hour}{3600\,s} \right)

T \approx 1.821\,h

6 0
3 years ago
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