A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the
2 answers:
The magnitude of the electric force exerted on a charge in an electric field is given by
where
q is the charge
E is the magnitude of the electric field
In this problem, we have a charge of , while the force exerted on it is
, so we can rearrange the previous formula to calculate the magnitude of the electric field:
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Answer:
The tension in the string is quadrupled i.e. increased by a factor of 4.
Explanation:
The tension in the string is the centripetal force. This force is given by
m is the mass, v is the velocity and r is the radius.
It follows that , provided m and r are constant.
When v is doubled, the new force, , is
Hence, the tension in the string is quadrupled.
Explanation:
It is given that,
Frequency of the laser light,
Time,
(a) Let is the wavelength of this light. It can be calculated as :
or
(b) Let n is the number of the wavelengths in one pulse. It can be calculated as :
n = 13440
Hence, this is the required solution.