A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the
2 answers:
The magnitude of the electric force exerted on a charge in an electric field is given by
where
q is the charge
E is the magnitude of the electric field
In this problem, we have a charge of , while the force exerted on it is
, so we can rearrange the previous formula to calculate the magnitude of the electric field:
You might be interested in
Answer:
Explanation:
Magnetic field near current carrying wire
=
i is current , r is distance from wire
B = 10⁻⁷ x
force on second wire per unit length
B I L , I is current in second wire , L is length of wire
= 10⁻⁷ x x 33 x 1
= 3234 x
This should balance weight of second wire per unit length
3234 x = .075
r = x 10⁻⁷
= .0043 m
= .43 cm .
The wavelength of the infrared radiation is λ = ×
m.
<h3>What is infrared radiation?</h3>
An infrared telescope is tuned to detect infrared radiation with a frequency of 9.45 THz.
We know that,
1 THz = 10¹² Hz
So,
f = 9.45 × 10¹² Hz
We need to find the wavelength of the infrared radiation.
λ=c/f
λ = 3×/9.45×
λ = 3.174 × m
The term "infrared radiation" (IR) refers to a part of the electromagnetic radiation spectrum with wavelengths between about 700 nanometers (nm) and one millimeter (mm). Longer than visible light waves but shorter than radio waves are infrared waves.
Electromagnetic radiation with wavelengths longer than those of visible light is known as infrared, also known as infrared light. Since it is undetectable to the human eye, The typical range of wavelengths considered to be infrared (IR) is from about 1 millimeter to the nominal red edge of the visible spectrum, or about 700 nanometers.
To learn more about infrared radiation from the given link:
#SPJ4