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Answer 1

1) The mass of 1 mole of virus is $5.4\cdot 10^6 kg$

2) There are 5.6 moles of viruses in an oil tanker

Explanation:

1)

One mole of a substance is the amount of that substance containing a number of particles equal to the Avogadro number:

$N_A = 6.022\cdot 10^{23}$

This means that 1 mole of this virus should contain a number of virus particles equal to $N_A$.

We know that the mass of 1 virus particle is

$m=9.0\cdot 10^{-12} mg = 9.0\cdot 10^{-18} kg$

Therefore, the mass of 1 moles of viruses is equal to the mass of a single virus particle multiplied by the number of virus particles in one mole, $N_A$:

$M=mN_A = (9.0\cdot 10^{-18})(6.022\cdot 10^{-23})=5.4\cdot 10^6 kg$

2)

In this problem, we have that the mass of the oil tanker is

$M_o = 3.0\cdot 10^7 kg$

We also know that the mass of one mole of virus is

$M=5.4\cdot 10^6 kg$

Therefore, we can find how many moles of viruses have a mass equal to the mass of the oil tanker by dividing the mass of the oil tanker by the mass of 1 mole of virus particles.

Mathematically, this is done by the following operation:

$N=\frac{M_O}{M}=\frac{3.0\cdot 10^7 kg}{5.4\cdot 10^6 kg}=5.6$

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