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baherus [9]
3 years ago
10

Justify air is a mixture not a compound

Chemistry
2 answers:
kirill115 [55]3 years ago
6 0
First we have to understand their definitions.

Mixture: a substance made by mixing other substances together physically.

Compound: made up or consisting of several parts or elements chemically.

Now that we understand their definitions we can justify and clarify that air is a mixture.

<span>The air is composed of many non-reactive gases such as nitrogen, hydrogen, methane, water vapor, carbon dioxide, etc. It can not be classified as a compound because compound means; several things (elements) compose a whole but chemically, and this previously mentioned gases are attached physically, not chemically.</span>
Andreas93 [3]3 years ago
4 0
A compound has to be chemically bonded, however, air is not chemically bonded.
This can be proven by freezing air. By freezing air, it yields different liquids at different temperature. Liquid nitrogen has a different boiling point than liquid oxygen.
If air was a compound, they would all have a single boiling point and a single freezing point.


Hope this helps :)
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The mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles of a substance by its molar mass. That is;

Mass of Arsenic = no. of moles of As × molar mass of As.

According to this question, 6.12 moles of arsenic was given and its molar mass is 74.92g/mol.

Mass of As = 6.12 mol × 74.92g/mol

Mass of As = 459g

Therefore, the mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

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A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

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Explanation:

Mass of the unknown compound = 5.024 mg

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Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

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For hydrogen, H:

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Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

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Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

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Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

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