<span>Q = mL
</span>
We need to know the latent heat of fusion, L, for 0 degrees.
L = 336 kJ/kg, m = 2kg
where L is the latent heat for vaporization
Q = 2 * 336 = 672 kJ
For conversion between 0 and 100 degree Celsius
Q = mcθ, specific heat capacity = 4.2 kJ/kgK
Q = 2*4.2* (100 - 0) = 840 kJ
For conversion to steam at 100 degrees Celsius
<span>Q = mL , L = latent heat of vaporization = 2256 kj/kg
</span>
Q = 2 * 2256 = 4512 kJ
Total heat = 672 + 840 + 4512 = 6024 kJ
= 6 024 000 J
But 1 calorie = 4.2 J
Therefore 6 024 000 J will be: 6 024 000/4.2 ≈ 1 434 286 Calories
≈ 1 434 kCalories
The correct answer is
<span>A) 0 m
</span><span>
In fact, the displacement is a vectorial quantity that corresponds to the difference between the initial and the final position of an object in motion. In this problem, the final position of the ball is equal to its initial position (because the ball returns back to where it was launched), so the displacement of the ball is zero.
</span>
Answer:
Explanation:
We are given that
Distance between plates=d=2.2 cm=
Using 
We have to find the magnitude of E in the region between the plates.
We know that the electric field for parallel plates
Where 
Substitute the values
Hence, the magnitude of E in the region between the plates=
