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Zolol [24]
3 years ago
13

A government agency estimated that air bags have saved over 14,000 lives as of April 2004 in the United States. (They also state

d that air bags have been confirmed as killing 242 people, and they stress that seat belts are estimated to save 11,000 lives a year.) Assume that a car crashes and has come to a stop when the air bag inflates, causing a 75.0 kg person moving forward at 15.0 m/s to stop moving in 0.0250 seconds. (a) What is the magnitude of the person's impulse? (b) What is the magnitude of the average force the airbag exerts on the person?
Physics
1 answer:
balu736 [363]3 years ago
6 0

To solve this problem it is necessary to apply the concepts related to momentum, momentum and Force. Mathematically the Impulse can be described as

I = F*t

Where,

F= Force

t= time

At the same time the moment can be described as a function of mass and velocity, that is

P = m\Delta v \rightarrow P=m(v_1-v_2)

Where,

m = mass

v = Velocity

From equilibrium the impulse is equal to the momentum, therefore

I = p

Ft = m(v_1-v_2)

PART A) Since the body ends at rest, we have the final speed is zero, so the momentum would be

p=m(v_1-v_2)

p = 75*0.15

p = 1125Kg\cdot m/s

Therefore the magnitude of the person's impulse is 1125Kg.m/s

PART B) From the equation obtained previously we have that the Force would be:

Ft = m(v_1-v_2)

F(0.025)= 1125

F= 45000N

Therefore the magnitude of the average force the airbag exerts on the person is 45000N

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Zolol [24]
With these questions, drawing it out would always help, the answer for this would be 90m if you add them all up. If it’s displacement, it would be 30m. But since it’s asking for the distance TRAVELED then it’s 90m

ANSWER: 90m

8 0
3 years ago
What is the longest wavelength of light that will emit electrons from a metal whose work function is?
alexdok [17]
 Best Answer:<span>  </span><span>hf = work function + KE 
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So hf = work function 
convert eV to joules, 2.4 x (1.6 x 10^-19) = 3.84 x 10^-19 
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6 0
3 years ago
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
Olenka [21]

Answer:

1.3m/s²

Explanation:

Given values in the first part: acceleration a, time t₁:

1) velocity v₀ = at_1

2) height h₀ =\frac{1}{2}at_1^2

Given values in the second part: acceleration -g,  time t₂:

3) height h = -\frac{1}{2}gt_2^2+v_0t_2+h_0

Combining equations 1,2,3 and setting h to zero:

0=-\frac{1}{2}gt_2^2+(at_1)t_2+\frac{1}{2}at_1^2\\ 0=a(t_1t_2+\frac{1}{2}t_1^2)-\frac{1}{2}gt_2^2

Solve for a with t₁ = 4s and t₂=2.1s:

a=\frac{1}{2}gt_2^2(\frac{1}{t_1t_2+\frac{1}{2}t_1^2})

7 0
3 years ago
At a rock concert, the sound intensity 1.0m in front of the bank of loudspeakers is 0.10 W/m^2. A fan is 30.0m from the loudspea
ElenaW [278]

Answer: The amount of energy transferred to each eardrum in one second is 6.2 \times 10^{-9} J.

Explanation:

Given: Intensity = 0.10 W/m^{2}

Now, at 30.0 m the intensity will be calculated as follows.

Intensity = \frac{(30.0 m)^{2}}{(1 m)^{2}}\\= 900

This means that the intensity is 900 times less assuming that the wave is spherical.

Hence, the new intensity is calculated as follows.

\frac{0.10 W/m^{2}}{900}\\= 1.11 \times 10^{-4} W/m^{2}

The area of ear drum is expressed as follows.

Area = \pi \times r^{2}\\= 3.14 \times (4.2 mm)^{2}\\= 5.54 \times 10^{-5} m^{2}\\

Formula used to calculate energy is as follows.

P = I \times a

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P = power or energy

I = intensity

a = area

Substitute the values into above formula as follows.

P = I \times a\\= 1.11 \times 10^{-4} W/m^{2} \times 5.54 \times 10^{-5} m^{2}\\= 6.2 \times 10^{-9} W

Thus, we can conclude that amount of energy transferred to each eardrum in one second is 6.2 \times 10^{-9} J.

7 0
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Iteru [2.4K]

Answer:

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Explanation:

3 0
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