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Answer:
the frequency is the fundamental and distance is L = ¼ λ
Explanation:
This problem is a phenomenon of resonance between the frequency of the tuning fork and the tube with one end open and the other end closed, in this case at the closed end you have a node and the open end a belly, so the wavelength is the basis is
λ = 4 L
In this case L = 19.4 cm = 0.194 m
let's use the relationship between wave speed and wavelength frequency and
v = λ f
where the frequency is f = 440 Hz
v = 4 L f
let's calculate
v = 4 0.194 440
v = 341.44 m / s
so the frequency is the fundamental and distance is
L = ¼ λ
Answer:
400 m/s
Explanation:
If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.
80 x 5 = 400
We will use the formula:
Q = ml
where Q is the heat, m is the mass of substance, and l is the latent heat of vaporization of the substance.
Q = 0.2 x 2.26 x 10³
Q = 452 kJ
12 MPH
I DIDNT do the math my brother did hes in colledge so good lucks guys
