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2 years ago

Which important safety measures should be taken during a hurricane? Select two options.

Physics

2 answers:

Roman55 [17]2 years ago

6 0

Answer:

1) move away from the windows.

When abrupt changes in pressure (produced by the hurricane) affect the windows, they can "explode" and be a serious danger for the people.

2) Go to the lowest level of the building.

Is safer than the upper levels because the lower levels suffer less from the strength of the hurricane (being closer to the ground increases the structural resistance), make sure that you have everything you may need in case of an emergency.

max2010maxim [7]2 years ago

6 0

Answer:

The answer is option A and B

Explanation:

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A falling object accelerates from -10.0 m/s to -30.0 m/s. how much time does it take?

Zepler [3.9K]

Answer:

2.04 s

Explanation:

v = at + v₀

(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)

t = 2.04 s

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3 years ago

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For a wave, the _____ the amplitude, the _____ energy the wave carries.

Rudik [331]

Answer:

<h2>HIGHER & MORE OR LARGER OR MORE </h2>

HENCE, THE ANSWER IS A. :)

Explanation:

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2 years ago

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24 A uniform electric field of magnitude 1.1×104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the elect

Tatiana [17]

Answer:

$44,000 Nm^2/C$

Explanation:

The electric flux through a certain surface is given by (for a uniform field):

$\Phi = EA cos \theta$

where:

E is the magnitude of the electric field

A is the area of the surface

$\theta$ is the angle between the direction of the field and of the normal to the surface

In this problem, we have:

$E=1.1\cdot 10^4 N/C$ is the electric field

L = 2.0 m is the side of the sheet, so the area is

$A=L^2=(2.0)^2=4.0 m^2$

$\theta=0^{\circ}$ , since the electric field is perpendicular to the surface

Therefore, the electric flux is

$\Phi =(1.1\cdot 10^4)(4.0)(cos 0^{\circ})=44,000 Nm^2/C$

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2 years ago

Help me quick!!! please!!

Rudik [331]

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is $w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J$

At this point we can simply apply the definition of power, that is $P = \frac wt$ , to get the power of the engine is $39.240 W$

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2 years ago

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What is the connection between change in momentum and impulse

Katena32 [7]

The change in momentum of an object equals the impulse applied to it

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2 years ago