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shusha [124]
3 years ago
14

Does a substance that evaporates more quickly (thus having a greater δt) have a higher or lower force of attraction to other mol

ecules in the liquid compared to a substance that evaporates more slowly (smaller δt)? explain.
Chemistry
1 answer:
AveGali [126]3 years ago
6 0
Substances that evaporate faster have a lower force of attraction between the molecules in the liquid. When the inter-molecular forces of attraction are weak, the amount of energy required to break the bonds will be lesser than for those with stronger inter-molecular forces. The weak bond can even be broken by room temperature.
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This scientist led a series of experiments that used high speed lightweight atoms called alpha particles to bombard very thin pi
ss7ja [257]

Answer:

B. Ernest Rutherford

Explanation:

Ernest Rutherford was a renown Physicist and a Physics Nobel price winner. In 1911 he proposed the planetary model of atom. When the experiment were conducted he proposed that the atom had a charged nucleus and are surrounded by electrons. This finding was the basis for subsequent studies on radioactivity.

3 0
3 years ago
Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas
hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of  CS_2 = 1.20 mole

Moles of  Cl_2 = 3.60 mole

Volume of solution = 1.00  L

Initial concentration of CS_2 = \frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M

Initial concentration of Cl_2 = \frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M

The given balanced equilibrium reaction is,

                 CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Initial conc.         1.20 M        3.60 M                  0                  0

At eqm. conc.     (1.20-x) M   (3.60-3x) M   (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

Now put all the given values in this expression, we get :

K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}

Given :Equilibrium concentration of CCl_4 , x = \frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M

K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}

K_c=0.36

Thus equilibrium constant at unknown temperature is 0.36

4 0
3 years ago
If you doubled the volume of a sample of gas and
Dimas [21]

Answer:

1125mL

Explanation:

this can be done using general gas law

3 0
3 years ago
Read 2 more answers
Which is the first stage of mitosis? Group of answer choices Anaphase Prophase Metaphase Telophase
ss7ja [257]

Answer:Prophase is the first stage of mitosis. In prophase,

Explanation:

3 0
3 years ago
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When one mole of sodium chloride dissociates in water, it produces: 1 mole of ions ½ mole of sodium ions 2 moles of ions ½ mole
adelina 88 [10]
Dissociation of NaCl in water is given as below,

                             NaCl ₍s₎    →    Na⁺ ₍aq₎  +  Cl⁻ ₍aq₎

According to this balanced equation the moles on RHS and LHS are as,

Moles on LHS,
                           NaCl ₍s₎   =   1 Mole

Moles on RHS,
                          Na⁺ ₍aq₎   =   1 Mole

                           Cl⁻ ₍aq₎   =    1 Mole
Result:
           
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
7 0
3 years ago
Read 2 more answers
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