A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full pow
1 answer:
Answer:
Explanation:
We can solve this problem by applying Newton's second law, which states that:
where
F is the net force on an object
m is the mass of the object
a is its acceleration
In this problem, we have:
m = 2300 + 2400 = 4700 kg is the total mass of the truck+the SUV
F = 18,000 N is the force exerted by the engine (that must be used to accelerate both the truck and the SUV)
Therefore, the acceleration on the truck-SUV system is
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Answer:
The torque on the pulley, when the system is motionless is approximately 9.81 N·m
Explanation:
The given parameters are;
The mass of the object = 2 kg
The friction between the rope and the pulley = 0
The mass of the rope, = 0.5 kg
The mass of the pulley, = 0.01 kg
The radius of the pulley, r = 0.25 m
The torque on the pulley, τ = I·α = F × D
The torque on the pulley, when the system is motionless, τ = F × D
Where;
F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N
D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m
Therefore;
τ = 19.62 N × 0.5 m = 9.81 N·m
The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.