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1 year ago

A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor

Physics

1 answer:

xxMikexx [17]1 year ago

3 0

The velocity with which the jumper leaves the floor is 5.1 m/s.

<h3>What is the initial velocity of the jumper?</h3>

The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v is the initial velocity of the jumper on the floor
h is the maximum height reached by the jumper
g is acceleration due to gravity

v = √(2 x 9.8 x 1.3)

v = 5.1 m/s

Learn more about initial velocity here: brainly.com/question/19365526
#SPJ1

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Scientists experimenting with two charged objects of 2.56 x 10-6 C and 3.34 x 10-7 C displayed a repulsion of 2.26 x 10-3 N. How

Pachacha [2.7K]

Answer:

The objects were 1.8m apart.

Explanation:

We will start stating the Coulomb's Law. It says that:

$F_e=\frac{Kq_1q_2}{r^{2}}$

Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant ( $K=8.9*10^{9} \frac{Nm^{2} }{C^{2} }$ in vacuum). Solving for the distance r we have:

$r=\sqrt{\frac{Kq_1q_2}{F_e} }$

Plugging the given values into this equation, we obtain:

$r=\sqrt{\frac{(8.9*10^{9}\frac{Nm^{2} }{C^{2} })(2.56*10^{-6}C)(3.34*10^{-7}C)}{2.26*10^{-3}N}}=1.8m$

In words, the two charged objects were 1.8m apart.

6 0

3 years ago

Read 2 more answers

Connecting many devices in a single socket does not affect the flow of current in a

eimsori [14]

Answer:- False

Explanation:-

False because it can leads to overloading and further to short circut.

7 0

3 years ago

A 70 kg football player running at 3m/s north tackles an 80kg player running at 1.5 m/s south. what is the magnitude and directi

dimulka [17.4K]

It could never actually happen like this, but the question is
looking for you to 'conserve' the momentum.

Momentum of a moving object is (mass) x (velocity).
Like velocity, momentum has a direction.
Momentum is one of those things that's 'conserved'.
That means that momentum can't appear out of nowhere, and
it doesn't disappear. The total after the collision is the same as
the total was before the collision.

Momentum of the skinny player:

   (70 kg) x (3 m/s north) = 210 kg-m/s north.

Momentum of the heavy player:

   (80 kg) x (1.5 m/s south) = 120 kg-m/s south .

Total momentum before the collision is

   (210 kg-m/s north) + (120 kg-m/s south)

   = 90 kg-m/s north .

It has to be the same after the collision.

   (mass) x (velocity) = 90 kg-m/s north.

The mass after the collision is 150 kg, because they get
tangled up and stuck together, and they move together.

(150 kg) x (velocity) = 90 kg-m/s north .

Divide each side
by 150 kg : velocity = (90 kg-m/s north) / (150 kg)

    = (90/150) (kg-m/s / kg north)

   = 0.6 m/s north .

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3 years ago

Why is the metric system used globally, but we use the US customary units?

tatuchka [14]

Answer:

The biggest reasons the U.S. hasn't adopted the metric system are simply time and money. When the Industrial Revolution began in the country, expensive manufacturing plants became a main source of American jobs and consumer products.

Explanation:

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3 years ago

An adult elephant has a mass of about 5.0 tons. An adult elephant shrew has a mass of about 50 grams. How far r from the center

Diano4ka-milaya [45]

Answer:

2023857702.507m

Explanation:

$f=\frac{GMm}{r^{2} }$

recall from newton's law of gravitation

G=gravitational constant

mshew=50g

melephant=5*10^3kg

rearth=radius of the earth 6400km or 6400000m

mearth= masss of the earth

Gm(shrew)m(earth)/r(earth)^2 = Gm(elephant)m(earth)/r^2

strike out the left hand side and right hand side variables

m(shrew)/r(earth)^2 = m(elephant)/r^2

r^2 = m(elephant).r(earth)^2 / m(shrew) .........make r^2 the subject of the equation

r^2= $(5*10^{3} *(6400000)^{2} )/.05$

r^2=40960000000000

r=2023857702.507m

4 0

3 years ago