Question

A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor

Answer 1

The velocity with which the jumper leaves the floor is 5.1 m/s.

What is the initial velocity of the jumper?

The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

• v is the initial velocity of the jumper on the floor
• h is the maximum height reached by the jumper
• g is acceleration due to gravity

v = √(2 x 9.8 x 1.3)

v = 5.1 m/s

Learn more about initial velocity here: brainly.com/question/19365526
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