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satela [25.4K]
1 year ago
15

A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor

Physics
1 answer:
xxMikexx [17]1 year ago
3 0

The velocity with which the jumper leaves the floor is 5.1 m/s.

<h3>What is the initial velocity of the jumper?</h3>

The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • v is the initial velocity of the jumper on the floor
  • h is the maximum height reached by the jumper
  • g is acceleration due to gravity

v = √(2 x 9.8 x 1.3)

v = 5.1 m/s

Learn more about initial velocity here: brainly.com/question/19365526
#SPJ1

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Which statements describe the Mercalli scale? Check all that apply.
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<h3><u>Full question:</u></h3>

Which statements describe the Mercalli scale? Check all that apply.

A. This scale measures seismic waves based on their size.

B. This scale rates an earthquake according to how much damage it causes.

C.This scale produces a single rating for earthquakes that reach the surface.

D. This scale uses Roman numerals to rank the damage caused by an earthquake.

E.This scale measures the magnitude of an earthquake based on the size of seismic waves.

<h3><u>Answer:</u></h3>

The Mercalli scale : This scale rates an earthquake according to how much damage it causes and This scale uses Roman numerals to rank the damage caused by an earthquake.

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The Modified Mercalli Intensity value ascribed to a particular site subsequent an earthquake has an extra significant means of severity to the nonscientist than the magnitude because intensity assigns to the outcomes really encountered at that position. This scale is comprised of 12 growing levels of intensity, denoted by Roman numerals, arranging from gradual shaking to catastrophic impairment.

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What will be the impact of continued water pollution and overuse on humans, and natural ecosystems?
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You are participating in a NASA traineeship, working with a group planning a new landing on Mars. Your supervisor has come up wi
aivan3 [116]

Answer:

h=17005.8 km

Explanation:

Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass M=6.39\times10^{23} kg at a distance r will be:

F=\frac{GMm}{r^2}

where G=6.67\times10^{-11}Nm^2/kg^2 is the gravitational constant.

This force is the centripetal force the satellite experiments, so we can write:

F=ma_{cp}=mr\omega^2=mr(\frac{2\pi}{T})^2=\frac{4\pi^2mr}{T^2}

Putting all together:

\frac{GMm}{r^2}=\frac{4\pi^2mr}{T^2}

which means:

r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}

Which for our values is:

r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km

Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km , which leaves us with:

h=r-R=20395.3km-3389.5 km=17005.8 km

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3 years ago
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