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Mama L [17]
3 years ago
12

Two wheels roll side-by-side without sliding, at the same speed. The radius of wheel 2 is one-half (1/2) the radius of wheel 1.

The angular velocity of wheel 2 is:
Physics
1 answer:
Lemur [1.5K]3 years ago
6 0

Answer:

w'=(1/2)w

Explanation:

In order to calculate the angular velocity of the second wheel, you use the following formula:

\omega=\frac{v}{r}      (1)

v: speed of the wheel 1 = speed of the wheel 2

r: radius of the wheel 1

For the second wheel you have:

r'=2r

You replace this value of r' in the following equation:

\omega'=\frac{v}{r'}=\frac{v}{2r}=\frac{1}{2}\frac{v}{r}=\frac{1}{2}\omega\\\\\omega'=\frac{1}{2}\omega

The angular velocity of the second wheel is one half of the angular velocity of the first wheel

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irga5000 [103]

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a) 95950 pascals

b) 137642.5 pascals

Explanation:

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b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

S.G=\frac{\rho_{fluid}}{\rho_{water}}

\rho_{liquid}=S.G*\rho_{water}

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P_{abs}=137642.5 Pa

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