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jeka57 [31]
3 years ago
7

An indicator is what type of compound?

Chemistry
2 answers:
Fofino [41]3 years ago
5 0

Answer:

c

Explanation:

OleMash [197]3 years ago
3 0
The letter (d.) strong base or acid would be the most appropriate answer to the question above. An indicator is a strong base or acid. Indicators are strong base and acid because through this you can determine if a compound is acid or base with its color.
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What is the name of this compound <br>Fe(NH3)5Cl4​
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Which of the following elements will form negative ions? Check<br> all that apply.
AleksandrR [38]

Answer:

Explanation:

Elements on the right side of the periodic table are very likely to form negative ions -- all of those except elements in the 8th or 18th column (depending on how your periodic table is numbered).

K and Mg are on the left side, so they will not form negative ions.

They give up 1 (for K) electron and 2 (for Mg) electrons which will leave plus charges for the ions.

On the other hand S and I are on the right side of the periodic table. They will take on electrons and hence be charged with a minus.

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2 years ago
What is true about all plutons? They form near Earth’s surface. They form below Earth’s surface. They cut across other rock laye
pishuonlain [190]

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<u>Explanation:</u>

Plutons are defined as the intrusive igneous rocks named as plutonic rocks which are formed when the magma gets cools down slowly and solidifies below the Earth's surface.

It is different from volcanic rocks which are formed when lava gets cools down and solidifies on the Earth's surface.

Hence, the correct answer is that they are formed below Earth's surface.

7 0
3 years ago
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The enthalpy of vaporization (ΔH°vap) of benzene is 30.7 kJ/mol at its normal boiling point of 353.3 K. What is ΔS°vap at this t
vazorg [7]

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.

Liquid\rightleftharpoons Gas

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To calculate \Delta S^o_{vap} for the reaction, we use the equation:

\Delta S^o_{vap}=\frac{\Delta H^o_{vap}}{T}

where,

\Delta S^o_{vap} = standard entropy change of vaporization

\Delta H^o_{vap} = standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol    (Conversion factor: 1 kJ = 1000 J)

T = temperature of the reaction = 353.3 K

Putting values in above equation, we get:

\Delta S^o_{vap}=\frac{30700J/mol}{353.3K}=86.9J/(mol.K)

Hence, the correct answer is Option c.

8 0
3 years ago
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