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lys-0071 [83]
3 years ago
15

What two elements were named after the United States?

Chemistry
2 answers:
Travka [436]3 years ago
6 0
Californium and tennessine
kenny6666 [7]3 years ago
5 0
Californium which is element 98, and americium:) those are a couple!! Hope that helps
You might be interested in
PLEASE HELPP!!!!
Alenkinab [10]

Answer:

Na the valency electrons is 1

The ion charge is positive 1

K the valency electrons is 1

The ion charge is positive 1

Explanation:

Mg the valency electron is 2 The ion charge is positive 2

Ca the valency electron is 2 The ion charge is positive 2

Al the valency electron is 3 The ion charge is positive 3

O the valency electron is 2 The ion charge

is negative 2

F the valency electron is 1 The ion charge is negative 1

Cl the valency electron is 1 The ion charge

is negative 1

N the valency electron is 3 The ion charge is negative 3

S the valency electron is 2 The ion charge is

negative 2

3 0
3 years ago
A person walking covers 5.20 m in 10.4 s. How fast is the person moving?
salantis [7]

Answer:

<h2>0.50 m/s</h2><h2></h2>

Explanation:

Velocity = distance over time

where distance = 5.20 m

                   time = 10.4 s.

velocity = <u>  5.20  m </u>

                  10.4 s.

            = 0.50 m/s  

8 0
3 years ago
Calculate the enthalpy of combustion of 1 mol decane, C10H22, (l), to form CO2 and H2O. ∆Hf0 for decane is —300.9 kJ/mol using t
worty [1.4K]

Answer:

heyy do you got the answer? i got that cuestion but i need the answer!!! did you finally get it?

Explanation:

5 0
3 years ago
If 20.0 ml of glacial acetic acid (pure hc2h3o2) is diluted to 1.40 l with water, what is the ph of the resulting solution? the
Y_Kistochka [10]

By using the formula, mass = density x volume, we calculate mass in grams

 20.0 mL CH₃COOH x (1.05 g / mL) = 21.0 g CH₃COOH 

To find the moles, molar mass of CH₃COOH = 60.05g/mol<span>

21.0 g </span>CH₃COOH x (1 mole CH₃COOH / 60.05 g CH₃COOH) = 0.350 moles CH₃COOH 

To find molarity,<span>

[</span>CH₃COOH] = moles CH₃COOH / L of solution = 0.350 / 1.40 = 0.250 M CH₃COOH<span> 

When </span>CH₃COOH is dissolved in water, it produces small and equal amounts of H₃O⁺+ and C₂H₃O₂⁻. 

<span>
Molarity ,         </span>CH₃COOH<span> + H</span>₂O <==> H₃O⁺ + C₂H₃O₂⁻ 

<span> <span>Initial                      0.250                          0           0 </span>
Change                      -x                            x            x 
Equilibrium            0.250-x                        x            x 

K</span>ₐ = [H₃O⁺][C₂H₃O₂⁻] / [HC₂H₃O₂] = (x)(x) / (0.250-x) = 1.8 x 10⁻⁵

<span>Since K</span>ₐ is relatively small, we can neglect the -x term after 0.250 to simplify 

<span>x</span>² / 0.250 = 1.8 x 10⁻⁵ 

x² = 4.5 x 10⁻⁶ 

<span> x = 2.1 x 10</span>⁻³<span> = [H</span>₃O⁺] 

pH = -log [H₃O⁺] = -log (2.1 x 10⁻³) = 2.68

8 0
3 years ago
Imagine that you are given the mass spectra of these two compounds, but the spectra are missing the compound names.
12345 [234]

The structures of the isomers and the m/z values of their peaks are not given in the question. The complete question is provided in the attachment

Answer:

Compound 2 (2,5-dimethylhexane) will not have the peaks at 29 and 85 m/z

Explanation:

The fragmentation of molecules by electron ionization of mass spectrometer occurs according to Stevenson's Rule, which states that "The most probable fragmentation is the one that leaves the positive charge on the fragment with the lowest ionization energy". This is much like the Markovnikov's Rule in organic chemistry which has predicted the formation of most stable carbocation and the addition of hydrogen halide to it.

The mass spectra of compound 1 (2,4-dimethylhexane) will contain all the m/z values mentioned in the question. Each peak indicate towards homologous series of fragmentation product of the compound 1. The first peak can be attributed to ethyl carbocation (m/z = 29), with the increase of 14 units the next peak indicates towards propyl carbocation (m/z = 43) and onwards until molecular ion peak of 114 m/z.

Compound 2 (2,5-dimethylhexane) structure shows that the cleavage  of C-C bond will not yield a stable ethyl and hexyl carbocation. Hence, no peaks will be observed at 29 and 85 m/z. The absence of these two peaks can be used to distinguish one isomer from the other.

5 0
3 years ago
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