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Ostrovityanka [42]
3 years ago
8

Compare and contrast chemical change and physical change

Chemistry
1 answer:
ki77a [65]3 years ago
3 0
Well physical would be if you have Clay and you molded into a new shape or if you put butter on your toes and it melts or water evaporating from the surface of the ocean chemical changes would be milk going sour jewellery tarnishing which means turning into a different color or rust bread putting it in the oven and turning it into toes or rust forming on the nail that is left outside
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A 0.6467-g portion of manganese dioxide was added to an acidic solution in which 1.1701 g of a chloride-containing sample was di
Katen [24]

Answer:

29.39% of AlCl₃ in the sample

Explanation:

Based on the reaction:

MnO₂(s) + 2Cl⁻ + 4H⁺ → Mn²⁺ + Cl₂(g) + 2H₂O

We can find the amount of chloride in solution with the amount of MnO₂ that reacted as follows:

<em>Initial mass MnO₂ = 0.6467g</em>

<em>Recovered mass = 0.3104g</em>

Mass that reacted = 0.6467g - 0.3104g = 0.3363g

<em>Moles MnO₂ -Molar mass: 86.9368g/mol-:</em>

0.3363g * (1mol / 86.9368g) = 3.868x10⁻³ moles MnO₂

<em>Moles Cl⁻:</em>

3.868x10⁻³ moles MnO₂ * (2mol Cl⁻ / 1mol MnO₂) = 7.737x10⁻³ moles Cl⁻

<em>Moles of AlCl₃ and mass -Molar mass AlCl₃: 133.34g/mol-:</em>

7.737x10⁻³ moles Cl⁻ * (1mol AlCl₃ / 3mol Cl⁻) = 2.579x10⁻³ moles AlCl₃

2.579x10⁻³ moles AlCl₃ * (133.34g / mol) =

<em>0.3439g of AlCl₃</em> are present in the sample.

The percent is:

0.3439g of AlCl₃ / 1.1701g * 100 =

<h3>29.39% of AlCl₃ in the sample</h3>

7 0
2 years ago
Both "Ode to the West wind" and "Ode for Melancholy"
Rama09 [41]
The answer that would best complete the given statement above would be option A. Both "Ode to the West wind" and "Ode for Melancholy" praise <span>something non-human. Hope this answers your question. Have a great day ahead!</span>
5 0
3 years ago
Write 0.00103 in scientific notation
Andrei [34K]

Answer:

1.03

Explanation:

You would take 0.00103 and move the decimal like this; 0001.03, we wouldn't have the zeroes in front of the one, as it can throw us off. Therefore, your answer would be 1.03.

Hope I helped! Don't hesitate to let me know if I made a mistake.

3 0
2 years ago
9. What type of bond is pictured in the image below?
mestny [16]

Answer:

metallic bond

because this diagram is electron gas theory which shows metallic bond

8 0
3 years ago
Carbon dioxide and helium which has a higher van der waals force of attraction between molecules ​
raketka [301]

Answer:

Carbon dioxide  

Explanation:

Neither helium nor carbon dioxide has a molecular dipole, so their strongest van der Waals attractive forces are London forces.

Helium is a small spherical atom with only a two electrons, so its atoms have quite weak attractions to each other.

CO₂ is a large linear molecule. It has more electrons than helium, so the attractive forces are greater. Furthermore, the molecules can align themselves compactly side-by-side and maximize the attractions (see below).

For example. CO₂ becomes a solid at -78 °C, but helium must be cooled to -272 °C to make it freeze (that's just 1 °C above absolute zero).

7 0
3 years ago
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