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krok68 [10]
3 years ago
12

Cutting down trees can decrease the amount of water vapor entering the air through the processes of ____?

Physics
1 answer:
AlexFokin [52]3 years ago
5 0

✿  Transpiration is the process by which water is carried through plants from roots and release water vapor through their leaves.

✿  Cutting down trees can decrease the amount of water vapor entering the air through the processes of <u>Transpiration</u>

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What physical property is being measured in the image below?
charle [14.2K]
The Liquid property
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A weather balloon is Floating at a constant height above Earth when it releases a pack hot instruments. If the pack hits the gro
Slav-nsk [51]

Answer:

The pack has fallen 275.6 m

Explanation:

The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where, choosing upward as positive direction:

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement

For the pack in this problem,

u = 0

v = -73.5 m/s

Solving for s, we find how far the packet has fallen:

s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m

And the negative sign means the direction of the displacement is downward.

5 0
3 years ago
A package is dropped from an airplane flying horizontally with constant speed V in the positive xdirection. The package is relea
k0ka [10]

Answer:

D=V*\sqrt{\frac{2H}{g} } -\frac{H}{4}

Explanation:

From the vertical movement, we know that initial speed is 0, and initial height is H, so:

Y_{f}=Y_{o}-g*\frac{t^{2}}{2}

0=H-g*\frac{t^{2}}{2}    solving for t:

t=\sqrt{\frac{2H}{g} }

Now, from the horizontal movement, we know that initial speed is V and the acceleration is -g/4:

X_{f}=X_{o}+V*t+a*\frac{t^{2}}{2}   Replacing values:

D=V*\sqrt{\frac{2H}{g} }-\frac{g}{4}*\frac{1}{2} *(\sqrt{\frac{2H}{g} })^{2}

Simplifying:

D=V*\sqrt{\frac{2H}{g} } -\frac{H}{4}

4 0
3 years ago
A student uses a spring to launch a marble vertically in the air. The mass of the marble is
Fed [463]

Answer:

the maximum height reached by the marble is 11.84 m.

Explanation:

Given;

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force applied to the string, F = 58 N

Apply the principle of conservation of energy;

elastic potential energy = gravitational potential energy

¹/₂fx = mgh

h = \frac{Fx}{2mg} \\\\h = \frac{58 \ \times \ 0.08}{2 \ \times \ 0.02 \ \times \ 9.8} \\\\h = 11.84 \ m

Therefore, the maximum height reached by the marble is 11.84 m.

5 0
3 years ago
Match the following:​
stellarik [79]

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bridges and automobiles :zinc metal

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3 years ago
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