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IrinaVladis [17]
2 years ago
10

Which statement about homeostasis is true?

Physics
1 answer:
Debora [2.8K]2 years ago
3 0

Answer: Homeostasis helps to maintain body equilibrium.

Explanation:

Homeostasis is defined as the maintenance of a fairly constant internal environment in an organism. Body fluids such as blood, lymph, and tissue fluids make up the internal environment of the body, hence by the action of the nervous and endocrine system, there levels are maintained at a body equilibrium, by the help of brain, which has overall control of homeostasis while other parts such as kidney, liver, skin, hormones are also involved.

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A man is 40 kg . calculate his weight.(g=10m/s^2)
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{ \large{ \bf{Weight = mg}}}

{ \large{ \bf{Mass = 40 \:  kg \:  \:  \:  \: (given)}}}

{ \large{ \bf{Weight = 40 \times 10}}}

{ \large{ \therefore{ \bf{ \red{ Weight = 400N}}}}}

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Que es un patrimonio histórico Nacional​
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If you could switch two movie characters, what switch would lead to the most inappropriate movies?
lesantik [10]
Hallar el valor numerico de 24m2n3p

4 0
3 years ago
¿Qué significa que la investigación debe ser replicable? Analiza.
Inga [223]

Significa que en su investigación, debe proporcionar suficiente información para que otras personas que lean su investigación puedan hacer la investigación nuevamente.

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3 years ago
A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

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Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
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