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skad [1K]
3 years ago
9

3. Provide two examples of static electric charge.

Physics
1 answer:
Rzqust [24]3 years ago
5 0

Answer: 1.  walking across a carpet and touching a metal door handle            2. pulling your hat off and having your hair stand on end.

Explanation

:)

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An electric car uses a 45-kW (160-hp) motor. If the battery pack is designed for 340V, what current would the motor need to draw
alukav5142 [94]

Answer:

Current = 132.35 A

The motor needs to draw 132.35 Amperes current from the battery.

Explanation:

The formula of electric power is given as follows:

Power = (Voltage)(Current)

Current = Power/Voltage

In this question, we have:

Power = 45 KW = 45000 W

Voltage of Battery Pack = 340 V

Current needed to be drawn = ?

Therefore,

Current = 45000 W/340 V

<u>Current = 132.35 A</u>

<u>The motor needs to draw 132.35 Amperes current from the battery.</u>

5 0
3 years ago
What are the animal life like in the tundra
beks73 [17]
The tundra is one of the coldest biomes so I would say that the animals have to be adapted. Maybe fur coats‍♀️they have to be warm and they also need food..I dunno I would think about how they live within the biome—(I added a picture of a tundra Biome)

5 0
3 years ago
Read 2 more answers
A load of 500N is carried by 200N effort in a simple machine having load distance 3m Calculate effort distance.​
vlada-n [284]

Answer:

<h2>2.5 m</h2>

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

500 \times 3 = 200 \times ED

multiply the numbers

1500 = 200 \times ED

Swipe the sides of the equation

200 \: ED \:  = 500

Divide both sides of the equation by 200

\frac{200 \: ED}{200}  =  \frac{500}{200}

Calculate

ED\:  = 2.5 \: m

Hope this helps..

best regards!!

5 0
3 years ago
At what velocity would a 5.0 kg dog have to run to have the same
Natali5045456 [20]

Answer:

The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s is 18 m/s

Explanation:

Given that the mass of the dog = 5.0 kg

The mass of the pig = 30 kg

The speed with which the pig is walking = 3.0 m/s

We have that linear momentum = Mass × Velocity

Therefore, the momentum of the pig, m₁ = 30 kg × 3.0 m/s = 90 kg·m/s

m₁ = 90 kg·m/s

The momentum of the dog m₂ = Mass of the dog × Velocity of the dog

Given that m₁ is to be equal to m₂, we have;

m₁ = 90 kg·m/s = m₂ = Mass of the dog × Velocity of the dog

90 kg·m/s = m₂ = 5.0 kg × Velocity of the dog

m₂ = 5.0 kg × Velocity of the dog = 90 kg·m/s

5.0 kg × Velocity of the dog = 90 kg·m/s

Velocity of the dog = 90 kg·m/s/(5.0 kg) = 18 m/s

The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s = 18 m/s.

4 0
3 years ago
Stamina is a measurement of how long you can do an activity? Question 4 options: True False
babymother [125]

Answer:

True

Explanation:

5 0
3 years ago
Read 2 more answers
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