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exis [7]
3 years ago
5

1.Which statement is true when two objects are 20 miles apart but one is much bigger?

Physics
2 answers:
ryzh [129]3 years ago
8 0
The first one is c? and 2nd is d i think
Paha777 [63]3 years ago
7 0

1. C.  Gravitational attraction exists between the two objects.

Explanation:

Gravitational attraction is always exerted between two objects which have mass, and its magnitude is given by:

F=G\frac{m_1 m_2}{r^2}

where G is the gravitational constant, m1 and m2 the masses of the two objects, and r the separation between them. Since the two objects have for sure non-zero masses m1 and m2, even if they are 20 miles apart, the value of the gravitational attraction F is non-zero, so the correct answer is C.


2. D.  Two atoms come together to form a molecule.

Explanation:

this outcome is actually caused by the electrostatic forces between the two atoms, not by gravitational force. In fact, gravitational force becomes relevant only when the masses of the two objects involved are large enough: this is the case for planets, stars, galaxies, and objects in the universe. However, two atoms have very small masses, so the gravitational force between them is really negligible. On this smaller scales, the electrostatic force is much stronger than the gravitational force, so the electrostatic force is the real responsible for the formation of bonds between atoms.

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Where should an object be placed in front of a concave mirror’s principal axis to form an image that is real, inverted, larger t
malfutka [58]
<em> I believe the answer is letter C.</em>
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I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b
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Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, P=hg\rho

Where h is the height that water is to reach, g is gravitational constant and \rho is the density, in this case, we assume \rho of pure water as 1000 Kg/m^3

Assuming g=10 m/s^{2}

P=8*10*1000=80000 Pa

<u>Question 2</u>

Pressure can also be found by the formula

P=0.5v^{2}\rho where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

P=0.5v^{2}\rho=hg\rho

Notice that \rho is common hence

0.5v^{2}=hg

Making V the subject of the formula

v^{2}=2hg

v=\sqrt 2hg

In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

v=\sqrt 2*10*6.4=11.3137085  m/s

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

v=\sqrt 2hg

Taking g as 9.8 and h now is 8m

v=\sqrt 2*8*9.8

v=12.52198067

Rounding off to 1 decimal place

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Solve for the length of the inclined plane if the angle equals 19.45 degrees.
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The length of the inclined plane is approximately 12 ft

The situation forms a right angle triangle.

<h3>Right triangle</h3>

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Therefore,

The length of the inclined plane is the hypotenuse of the triangle. The length of the inclined plane can be found using trigonometric ratios.

height = 4 ft

angle(∅) = 19.45°

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Therefore, the length of the inclined plane is approximately 12 ft

learn more on inclined plane:brainly.com/question/14163589?referrer=searchResults

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