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pshichka [43]
3 years ago
12

A substance floats or sinks in another because of its relative

Chemistry
1 answer:
mart [117]3 years ago
6 0
A substance floats or sinks in another because of its relative density. Take ice floating in water for example. Water is more dense than ice so ice floats.

Mass is incorrect as the buoyancy or ability of an object to float depends on the mass per volume, which is equivalent to density.
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What is the main elements in a plastic cup
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<span>Polyethylene terephthalate formed into a cup shape. The components of polyethylene terephthalate are carbon, hydrogen and oxygen.</span>
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What is the main difference between a generator and an electric motor? _______
garri49 [273]

Answer:

A generator produces electricity and an electric motor consumes electricity

4 0
3 years ago
Read 2 more answers
How are natural polymers and synthetic polymers similar?
Anna [14]

Answer: C) Both are made up of monomers that are linked by covalent bonds

Explanation: Polymers are large molecules which are formed by combination of small repeating units called as monomers.

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All the polymers, whether natural or synthetic are made up of monomers and are joined by covalent bonds.


4 0
3 years ago
Calculate the volume of an object (in mL) if the density of the object is 4.08 g/mL and the mass of the object is 10.02 g.
slega [8]

Answer:

<h2>The answer is 2.5 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of object = 10.02 g

density = 4.08 g/mL

The volume of the object is

volume =  \frac{10.02}{4.08}  \\  = 2.4558823...

We have the final answer as

<h3>2.5 mL to one decimal place</h3>

Hope this helps you

6 0
3 years ago
A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu
klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}

<u>T₂ = 19.95°C</u>

6 0
3 years ago
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