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Stels [109]
1 year ago
15

How does carbonation affect melting point

Chemistry
1 answer:
FromTheMoon [43]1 year ago
3 0
The sodium in soda lowers the melting point and makes the ice melt more slowly than it would in plain water because with the addition of any substance, there are fewer free water molecules available to form bonds together and freeze
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When is the potential energy between two atoms at zero?
ExtremeBDS [4]

Answer:

When two atoms are very far apart, the potential energy approaches zero.

8 0
3 years ago
50 points!! i need 3 answers!!!
tester [92]
Option E, Real gas particles have more complex interactions than ideal gas particles.

In ideal gases, there is absolutely no interaction between any atoms. At all. Atoms simply don't bump into each other in ideal gases.

Obviously, you know that's unrealistic. In real gases, atoms collide into each other all the time.

-T.B.
3 0
3 years ago
Read 2 more answers
What is the molarity of a NaCl solution containing 9.0<br> moles of NaCl in 3.0 L of solution?
ss7ja [257]

Answer:

3 M

Explanation:

Molarity equation: M = n/v

n = moles of solute

v = liters of solution

9 moles of NaCl / 3 L

9/3 = 3 M

4 0
3 years ago
A drinking water plant adds 500 grams of fluoride to a water tank containing 500,000 liters of drinking water. what is the conce
nlexa [21]
Answer is: <span>concentration of fluoride in the water in parts-per-million is 1 ppm.
</span>Parts-per-million (10⁻⁶) is<span> present at one-millionth of a </span>gram per gram of sample solution, f<span>or example mg/kg.
</span>m(fluoride) = 500 g · 1000 mg/g = 500000 mg.
m(water) = d(water) · V(water).
m(water) = 1 kg/L · 500000 L.
m(water) = 500000 kg.
arts-per-million = 500000 mg ÷ 500000 kg = 1 mg/kg = 1 ppm.
5 0
3 years ago
Which relationship can be used to aid in the determination of the heat absorbed by bomb calorimeter? 
NARA [144]

Answer:

ΔH = q_{p}

Explanation:

In a calorimeter, when there is a complete combustion within the calorimeter, the heat given off in the combustion is used to raise the thermal energy of the water and the calorimeter.

The heat transfer is represented by

q_{com} = q_{p}

where

q_{p} = the internal heat gained by the whole calorimeter mass system, which is the water, as well as the calorimeter itself.

q_{com}  = the heat of combustion

Also, we know that the total heat change of the any system is

ΔH = ΔQ + ΔW

where

ΔH = the total heat absorbed by the system

ΔQ = the internal heat absorbed by the system which in this case is q_{p}

ΔW = work done on the system due to a change in volume. Since the volume of the calorimeter system does not change, then ΔW = 0

substituting into the heat change equation

ΔH = q_{p} + 0

==> ΔH = q_{p}

5 0
3 years ago
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