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cricket20 [7]
3 years ago
6

In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56

ATM AT 100ºc. What would happen to these pressures if a catalyst were added to the mixture?
Chemistry
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

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Among the factors that affect the solubility of a substance are type of solvent and temperature.
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7 0
3 years ago
What mass of oxalic acid dihydrate, H2C2O4•2H2O, is needed to make a 0.357 M solution of oxalic acid in a 250.0mL volumetric fla
GalinKa [24]

Molarity is expressed as the number of moles of solute per volume of the solution. The mass of oxalic acid dihydrate needed for the solution is calculated as follows:

Amount in moles: (0.357 mol H2C2O4•2H2O / L) (.250 L ) = 0.0893 mol H2C2O4•2H2O


Amount in mass : 0.0893 mol H2C2O4•2H2O (126.08 g / mol ) = 11.2589 g H2C2O4•2H2O


Hope this answers the question. Have a nice day.

5 0
3 years ago
Gases A and B are confined to a cylinder and piston and react to form product C. As the reaction occurs, the system loses 1189 J
aliya0001 [1]

Answer:

The change in the internal energy of the system -878 J

Explanation:

Given;

energy lost by the system due to heat, Q = -1189 J (negative because energy was lost by the system)

Work done on the system, W = -311 J (negative because work was done on the system)

change in internal energy of the system, Δ U = ?

First law of thermodynamics states that the change in internal energy of a system (ΔU) equals the net heat transfer into the system (Q) minus the net work done by the system (W).

ΔU = Q - W

ΔU = -1189 - (-311)

ΔU = -1189 + 311

ΔU = -878 J

Therefore, the change in the internal energy of the system -878 J

8 0
4 years ago
Sulfur and magnesium both have two valence electrons.<br> a. True<br> b. False
Nezavi [6.7K]
It would be false sulfur has 6 
3 0
4 years ago
How does the reactivity of nonmetals change as you move from left to right across the periodic table?
Rudiy27

Answer:

Metallic character refers to the level of reactivity of a metal. Non-metallic character relates to the tendency to accept electrons during chemical reactions. Metallic tendency increases going down a group. Non-metallic tendency increases going from left to right across the periodic table.

Explanation:

I hope this helps :)

4 0
3 years ago
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