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Bumek [7]
3 years ago
10

One difference between d-glucose and l-glucose is

Chemistry
1 answer:
dimulka [17.4K]3 years ago
6 0
<span>only D-glucose is found in disaccharides and polysaccharides.</span>
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You have 17 liters of gas at STP. If the temperature rises to 94C and while the volume decreases to 12 liters, what will the ne
fenix001 [56]

Answer:

P_2=1.90atm

Explanation:

Hello!

In this case, according to the ideal gas equation ratio for two states:

\frac{P_1V_1}{P_2V_2} =\frac{n_1RT_1}{n_2RT_2}

Whereas both n and R are cancelled out as they don't change, we obtain:

\frac{P_1V_1}{P_2V_2} =\frac{T_1}{T_2}

Thus, by solving for the final pressure, we obtain:

\frac{P_2V_2}{P_1V_1} =\frac{T_2}{T_1}\\\\P_2=\frac{T_2P_1V_1}{V_2T_1}

Now, since initial conditions are 1.00 atm, 273.15 K and 17 L and final temperature and volume are 94 + 273 = 367 K and 12 L respectively, the resulting pressure turns out to be:

P_2=\frac{367K*1.00atm*17L}{12L*273.15K}\\\\P_2=1.90atm

Best regards!

7 0
3 years ago
A 25-mL solution of H2SO4 is completely neutralized by 18 mL of 1.0M NaOH. What is the concentration of the H2SO4?
Charra [1.4K]
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
     = 25/1000 liter
     = 0.025 liter
V2 = 18 ml
      = 18/1000 liter
      = 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
      = (1 * 0.018)/0.025
      = 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
5 0
3 years ago
Read 2 more answers
Describe the ways you can know that a chemical reaction has occurred.
Bad White [126]
Signs that a chemical reaction is occurring are: 1. change in color 2. change in odor 3. change in pH, as in changes from acid to base or base to acid
8 0
4 years ago
Read 2 more answers
If the molar mass of NaCl is 58.44 g/mol, what amount of NaCl (in mol) is contained in 250.0 mg of NaCl?
4vir4ik [10]

Answer: 0.004 moles

Explanation:

Amount of substance= mass/ molar mass

Mass= 250mg or 0.25g

Molar mass= 58.44gmol-1

Amount= 0.25/58.44

= 0.004 moles

5 0
3 years ago
What is the molecular formula of a compound with an empirical formula of C4H9 and a gram-formula mass of 114.0 g/mole?
hodyreva [135]
The formula is easy:

Gram formula mass
----------------------------
Emprical Formula

So if we plug in our own numbers,

114.0
--------
57.116 

We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.

2(C4H9) becomes C8H18.

Our molecular formula is C8H18.
Hope I could help!
6 0
3 years ago
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