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Bumek [7]
3 years ago
10

One difference between d-glucose and l-glucose is

Chemistry
1 answer:
dimulka [17.4K]3 years ago
6 0
<span>only D-glucose is found in disaccharides and polysaccharides.</span>
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nydimaria [60]
Is the answer Radiation
4 0
2 years ago
I have a 4 amino acid peptide of unknown sequence with a curious titration profile around pH = 6. If Iknow that the peptide N-te
netineya [11]

Answer:

c. Histidine

Explanation:

Histidine is a compound that is normally used for the generation of protein. Three amino acids commonly have basic side chain when the pH is neutral. The conjugate acid in histidine has a pKa of approximately 6. Based on the description of the experimental analysis provided in the statement, the right option is option c.

4 0
3 years ago
Which of these is a benefit of fuel cell cars?
Otrada [13]

Answer:

A.

Explanation:

There are no vehicle emissions other than water vapor. This means no pertroleum products and no fossil fuels. :)

-Sienna Sushi

5 0
3 years ago
Read 2 more answers
Describe what half-life is.<br> answer in a paragraph please.
dangina [55]

Half-life is defined as the quantity to reduce to half of its initial value.

Explanation:

The term half-life is generally used in nuclear physics which describes how long a stable atom can survive a radioactive decay or how quickly an unstable stable atom can undergo radioactive decay. Half-life is a constant and does not have any units.

<u>The formula to calculate half-life: </u>

N(t) = \bold{N_{0} e^{-\lambda t}}

Here N(t) is the quantity which is “not decayed”.

N_0 is the “initial quantity” of the substance.

λ is the “decay constant”

4 0
3 years ago
A photon of light has an energy of 1.83 x 10-18). What is the wavelength of this light? Does this light fall in the IR, visible,
Scrat [10]

Answer:

1.09 × 10⁻⁷ m

UV region

Explanation:

Step 1: Given and required data

Energy of the photon of light (E): 1.83 × 10⁻¹⁸ J

Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Calculate the wavelength (λ) of this photon of light

We will use the Planck-Einstein's relation.

E = h × c/λ

λ = h × c/E

λ = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/1.83 × 10⁻¹⁸ J = 1.09 × 10⁻⁷ m

This wavelenght falls in the UV region of the electromagnetic spectrum.

4 0
2 years ago
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