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2 years ago

If you had 2 oxygen atoms and 1 hydrogen atom, could you form a molecule?

Chemistry

1 answer:

Brrunno [24]2 years ago

8 0

Answer:

Yes!

Explanation:

You certainly could form something. It would be written as H02 and it is called Hydroperoxyl. This is formed by the transfer of a hydrogen atom to an oxygen atom.

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The following is known as the thermite reaction: 2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(s) This highly exothermic reaction is used for wel

Colt1911 [192]

Answer:

$\Delta H_{rxn}=-847.6\ KJ/mol.$

Explanation:

The balanced chemical equation is:

$2Al(s)+Fe_2O_3(s)-->Al_2O_3+2Fe(s)$

Now, standard values of $\Delta H_f\ of\ all\ participants\ of\ reaction.$

$\Delta H_f(Al_2O_3)=-1669.8\ KJ/mol\\\Delta H_f(Fe_2O_3)=-822.2\ KJ/mol\\\Delta H_f(Al(s))=0\ KJ/mol\\\Delta H_f(Fe(s))=0\ KJ/mol\\$

Now, We know $\Delta H_{rxn}=\Delta H_{products}-\Delta H_{reactants}$

Putting all values of $\Delta H_f$ to above equation.

We get,

$\Delta H_{rxn}=-847.6\ KJ/mol.$

Hence, this is the required solution.

6 0

3 years ago

Given the following reaction: 3D(g) + E(g) + 2F(g) → 5G(g) + 4H(g)

evablogger [386]

Answer:

Explanation:

Hello,

The law of mass action, allows us to know the required amounts, thus, for this chemical reaction it is:

$\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}$

Now, we answer:

(a)

$\frac{d[H]}{dt}=4*\frac{1}{-3} *(-0.12M/s)=0.16M/s$

(b)

$\frac{d[E]}{dt}=-1*\frac{1}{5} *(0.2M/s)=-0.04M/s$

$r=\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}$

Thus, any of the available expressions are suitable to quantify the rate of the reaction.

Best regards.

4 0

3 years ago

Balance each reaction and write its reaction quotient, Qc:(b) SF₆(g) + SO₃(g) → SO₂F₂(g)

IceJOKER [234]

When we balance the given equation

SF₆(g) + SO₃(g) → SO₂F₂(g)

We will get

SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)

Solution:

Balancing the given equaation

SF₆(g) + SO₃(g) → SO₂F₂(g)

We have to balance the given number of O

SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)

We get balanced equation

SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)

The reaction quotient will be

Qc = [product] / [reactant]

Qc = [SO₂F₂(g)] / [SF₆(g) + SO₃(g)]

To learn more click the given link

brainly.com/question/16025432

#SPJ4

4 0

2 years ago

What measurements must you make to find the density of a sample of matter

Xelga [282]

You would have to look for the mass of the sample and the volume of the sample.

5 0

4 years ago

Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?

Rufina [12.5K]

Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t = ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr

6 0

4 years ago