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blagie [28]
2 years ago
9

If you had 2 oxygen atoms and 1 hydrogen atom, could you form a molecule?

Chemistry
1 answer:
Brrunno [24]2 years ago
8 0

Answer:

Yes!

Explanation:

You certainly could form something. It would be written as H02 and it is called Hydroperoxyl. This is formed by the transfer of a hydrogen atom to an oxygen atom.

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When a kettle is placed on the stove and water begins to boil, the hotter water at the bottom begins to rise and the
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Answer:

The cooler water is denser

Explanation:

Convection drives the boiling of water placed on a stove in a kettle.

During convection, heat is circulated by density differences in portions of a fluid.

Convection is a form of heat transfer in fluids especially gas and liquid.

  • In boiling water, the heat is supplied to the base of the stove.
  • The water at the bottom on heat becomes lighter as the molecules gain more kinetic energy.
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  • This exchange sets up convection cells in the kettle.
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2 years ago
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This is agree or disagree I need help ASAP!!
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Which of the following is generally true of female bones in relationship to male bones?
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3 years ago
During the titration of a weak acid and a strong base, you would expect the ph at the endpoint of titration to be ____.
riadik2000 [5.3K]

Answer is: b. more than 7.

The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop.

For example, basic salt sodium acetate CH₃COONa is formed from the reaction between weak acid (in this example acetic acid CH₃COOH) and strong base (in this example sodium acetate NaOH).

Balanced chemical reaction of acetic acid and sodium hydroxide:

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Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base react quantitatively with each other.

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3 years ago
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If you have 85g of sulfur dioxide at STP, how many moles do you have?
Step2247 [10]

Answer: 1.32

Explanation:

Given

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The number of moles of sulfur dioxide is

\Rightarrow n=\dfrac{85}{64}\\\\\Rightarrow n=1.32\ \text{mol}

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