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AfilCa [17]
3 years ago
6

A student pulls a 2.0-kg object to the left with a force of 30 N, while another student is pulling against the object in the opp

osite direction with a force of 20 N. What is the acceleration of the object?
5 m/s2, left

5 m/s2, right

20 m/s2, left

20 m/s2, right
Physics
1 answer:
alex41 [277]3 years ago
5 0

Answer:

5 m/s2, left

Explanation:

We can solve the problem by applying Newton's second law of motion, which  states that:

\sum F=ma

where:

\sum F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have:

\sum F=30 N - 20 N = 10 N (to the left) is the net force on the object

m = 2.0 kg is the mass

So, the acceleration is:

a=\frac{\sum F}{m}=\frac{10}{2.0}=5.0 m/s^2

in the same direction as the force (left).

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The flywheel of a motor has a mass of 300.0 kg and a radius of 55 cm. If the motor can exert a torque of 2000.0 N . m on this fl
Alexeev081 [22]

Answer:

Explanation:

Work done by torque is given as

Word one = torque × angular displacement

W = ​ τ × θ

Given that,

τ = 2000Nm

Mass of motor = 300kg

Radius r = 55cm = 0.55m

Work done by wheel in first t= 23second.

Now we need to find the angular displacement

We know that,

τ = I•α

Moment of inertia of wheel

I = MR²

I = 300 × 0.55²

I = 90.75 kgm²

Then, τ = I•α

α = τ / I

α = 2000/90.75

α = 22.04rad/s²

Then, using circular motion,

∆θ = wit + ½αt²

wi = 0rad/s

∆θ = ½αt²

∆θ = ½ × 22.04 × 23²

∆θ = 5829.2 rad.

Then,

Work done?

W = ​ τ × θ

W = 2000 × 5829.2

W = 1.17 × 10 ^7 J

7 0
3 years ago
Describe the movement of sperm in the female reproductive system. State the different structures that it must pass in order to m
saw5 [17]

Answer:

After a male ejaculates, many sperms move to the upper vagina (via contractions from the vagina) through the cervix and across the length of the uterus, reaching the fallopian tubes. Here they will meet the egg cell ready to be fertilized

5 0
3 years ago
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.5 s
blondinia [14]

Answer:

1.2 m/s

0.31 m

0.15 m

Explanation:

Time period is

T=2.5\times 2\\\Rightarrow T=5\ s

Frequency is

f=\dfrac{1}{T}\\\Rightarrow f=\dfrac{1}{5}\\\Rightarrow f=0.2\ Hz

Velocity is given by

v=f\lambda\\\Rightarrow v=0.2\times 6\\\Rightarrow v=1.2\ m/s

The waves are traveling at 1.2 m/s

Amplitude is given by

A=\dfrac{d}{2}\\\Rightarrow A=\dfrac{0.62}{2}\\\Rightarrow A=0.31\ m

Amplitude is 0.31 m

If d = 0.3 m

A=\dfrac{0.3}{2}=0.15\ m

The amplitude would be 0.15 m. The speed would remain the same.

8 0
4 years ago
HELLLLLP PLEASE, thank u :)
MrRa [10]

Answer:

Option B. 3.0×10¯¹¹ F.

Explanation:

The following data were obtained from the question:

Potential difference (V) = 100 V.

Charge (Q) = 3.0×10¯⁹ C.

Capacitance (C) =..?

The capacitance, C of a capacitor is simply defined as the ratio of charge, Q on either plates to the potential difference, V between them. Mathematically, it is expressed as:

Capacitance (C) = Charge (Q) / Potential difference (V)

C = Q/V

With the above formula, we can obtain the capacitance of the parallel plate capacitor as follow:

Potential difference (V) = 100 V.

Charge (Q) = 3.0×10¯⁹ C.

Capacitance (C) =..?

C = Q/V

C = 3.0×10¯⁹ / 100

C = 3.0×10¯¹¹ F.

Therefore, the capacitance of the parallel plate capacitor is 3.0×10¯¹¹ F.

7 0
4 years ago
All biomes don’t have the same level of biodiversity. What seems to be the optimal conditions for high biodiversity?
irinina [24]

Answer:

See the answer below

Explanation:

The optimal conditions for high biodiversity seem to be a <u>warm temperature</u> and <u>wet climates</u>.

<em>The tropical areas of the world have the highest biodiversity and are characterized by an average annual temperature of above 18 </em>^oC<em> and annual precipitation of 262 cm. The areas are referred to as the world's biodiversity hotspots. </em>

Consequently, it follows logically that the optimal conditions for high biodiversity would be a warm temperature of above 18 ^oC and wet environment with annual precipitation of not less than 262 cm.

The variation in temperature and precipitation across biomes can thus be said to be responsible for the variation in the level of biodiversity in them.

6 0
3 years ago
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