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Fiesta28 [93]
2 years ago
6

A space shuttle is flying north at 6,510 m/s. It

Physics
1 answer:
Maksim231197 [3]2 years ago
7 0

Answer:

7808 m/s

Explanation:

Find NE velocity after 60 s  of acceleration in that direction:

  = a t  =  28.4 m/s^2 * 60 s = 1704  m/s

    Vertical component = 1704 sin 45 = 1204.9 m/s

     Horiz component = 1704 cos 45 = 1204.9  m/s

Add the two vertical components

  6510 + 1204.9 = 7714.9 m/s = vertical velocity

Pythagorean theorem to find resultant of vertical and horiz  v's

Vf ^2 = 1204.9^2   + 7714.9^2 0

Vf = 7808. m/s

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Answer:

a)  a = - 0.106 m/s^2  (←)

b) T = 12215.1064 N

Explanation:

If

F₁ = 9*1350 N = 12150 N   (→)

F₂ = 9*1365 N = 12285 N  (←)

∑Fx = M*a = (M₁  +M₂)*a           (→)

F₁ - F₂ = (M₁  +M₂)*a        

→       a = (F₁ - F₂) / (M₁  +M₂ ) = (12150-12285)N/(9*68+9*73)Kg

→       a = - 0.106 m/s^2            (←)

(b) What is the tension in the section of rope between the teams?

If we apply  ∑Fx = M*a   for the team 1

F₁ - T = - M₁*a  ⇒   T = F₁ + M₁*a  

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⇒ T = 12215.1064 N

If we choose the team 2 we get

- F₂ + T = - M₂*a  ⇒   T = F₂ - M₂*a  

⇒   T = 12285 N - (9 * 73 Kg)*(0.106 m/s^2)

⇒ T = 12215.1064 N

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