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Fiesta28 [93]
2 years ago
6

A space shuttle is flying north at 6,510 m/s. It

Physics
1 answer:
Maksim231197 [3]2 years ago
7 0

Answer:

7808 m/s

Explanation:

Find NE velocity after 60 s  of acceleration in that direction:

  = a t  =  28.4 m/s^2 * 60 s = 1704  m/s

    Vertical component = 1704 sin 45 = 1204.9 m/s

     Horiz component = 1704 cos 45 = 1204.9  m/s

Add the two vertical components

  6510 + 1204.9 = 7714.9 m/s = vertical velocity

Pythagorean theorem to find resultant of vertical and horiz  v's

Vf ^2 = 1204.9^2   + 7714.9^2 0

Vf = 7808. m/s

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A spring with force constant of 59 N/m is compressed by 1.3 cm in a hockey game machine. The compressed spring is used to accele
Furkat [3]

Answer:

The puck moves a vertical height of 2.6 cm before stopping

Explanation:

As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.

So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.

Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So

1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².

Substituting the kinetic energy of the puck for the potential energy of the spring, we have

1/2kx² = mgh

h = kx²/2mg

= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)

= 0.009971 Nm/0.38416 N

= 0.0259 m

= 2.59 cm

≅ 2.6 cm

So the puck moves a vertical height of 2.6 cm before stopping

3 0
3 years ago
PLEASE HELP!! DUE SOON!!!
max2010maxim [7]

Answer:

See attached file :)

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4 0
2 years ago
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Describe an Earth system that recycles resources in a way that is similar to how a spacecraft recycles resources.
weqwewe [10]

Answer:

the differenced trash

3 0
3 years ago
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All the bodies whether large or small fall with​
Alona [7]
Gravity as all bodies whether large or small have mass.
7 0
3 years ago
A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

P = VI

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}

b) The resistance <em>R</em><em> </em>of the heater is

P = VI = (IR)I = I^2R

where V= IR is our familiar Ohm's Law.

\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}

R = 110.8\:Ω

8 0
3 years ago
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