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svetlana [45]
3 years ago
11

Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two

charges of magnitude 2*Q and 2*Q when held at a distance r/2.?
Physics
1 answer:
Pepsi [2]3 years ago
4 0

Answer:197.504 N

Explanation:

Given

Two Charges with magnitude Q experience a  force of 12.344 N

at distance r

and we know Electrostatic force is given

F=\frac{kq_1q_2}{r^2}

F=\frac{kQ\cdot Q}{r^2}

F=\frac{kQ^2}{r^2}

Now the magnitude of charge is 2Q and is at a distance of \frac{r}{2}

F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}

F'=16F

F'=197.504 N

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Answer:

lowest frequency = 535.93 Hz

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Explanation:

given data

length L = 32 cm = 0.32 m

to find out

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solution

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so

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lowest frequency will be = \frac{343}{2(0.32)}

lowest frequency = 535.93 Hz

and

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wavelength = 0.08575 m

so distance =  \frac{wavelength}{2}   ..............3

distance =  \frac{0.08575}{2}  

distance = 0.0425 m

so distance  between adjacent anti nodes is 4.25 cm

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