Please help me complete the following table

What is the amount of aluminum chloride produced from 40 moles of aluminum and excess chlorine?

Marrrta [24]

Answer:

is it 26.98

Explanation:

6 0

3 years ago

PLS HELP Answer this question and I will mark you the braninliest! <3

Tpy6a [65]

Answer:

the left one

Explanation:

heavier means it goes faster

5 0

3 years ago

What does the law of conservation of energy state about energy in a closed system?

dezoksy [38]

Answer:

Energy cannot be created or destroyed.

Explanation:

According to the law of conservation of energy, energy can neither be created nor it can be destroyed. Energy can only be transformed from one matter to another. The conservation of energy remains constant in an isolated system. The law is applicable in the system that does not exchange energy in the environment. Energy changes its form but remains constant.

4 0

3 years ago

Read 2 more answers

Pentaborane−9 (B5H9) is a colorless, highly reactive liquid that will burst into flames when exposed to oxygen. The reaction is

mote1985 [20]

Answer : The heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

The equilibrium reaction follows:

$2B_5H_9(l)+12O_2(g)\rightleftharpoons 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(n_{(B_2O_3)}\times \Delta H^o_f_{(B_2O_3)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(B_5H_9)}\times \Delta H^o_f_{(B_5H_9)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]$

We are given:

$\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(5\times -1271.94)+(9\times -285.83)]-[(2\times 73.2)+(12\times 0)]=-9078.57kJ/mol$

Now we have to calculate the heat released per gram of the compound reacted with oxygen.

From the reaction we conclude that,

As, 2 moles of compound released heat = -9078.57 kJ

So, 1 moles of compound released heat = $\frac{-9078.57}{2}=-4539.28kJ$

For per gram of compound:

Molar mass of $B_5H_9$ = 63.12 g/mole

$\Delta H^o_{rxn}=\frac{-4539.28}{63.12}=-71.915kJ/g$

Therefore, the heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

7 0

3 years ago

Help asap help show work I need an A

MrRissso [65]

Answer: 17 (a) 360,000 ms 18 (a) 0.245 s

(b) 4.800 kg (b) 500 cm

(c) 560.0 dm (c) 68.00 m

(d) 72,000 mg (d) 0.025 Mg

Explanation:

Use the following table. Note the direction you are going to:

Right means move decimal to the right. Left means move decimal to the left.