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Harrizon [31]
1 year ago
13

A 13.00 g sample of citric acid reacts with an excess of baking soda as shown in the equation.

Chemistry
2 answers:
UNO [17]1 year ago
8 0
From Law of definite proportion
You can compare this
Citric acid (Mw) / 3CO2 (Mw) = Citric acid (g) / 3CO2 (g)
So (12)6+(1)8+(16)7 / 3[12 + (16)2] = 13 / 3CO2
192 / 132 = 13 / CO2
You can get 3CO2 = 8.93 g
PolarNik [594]1 year ago
4 0

Answer:

eheheehehehszndn!jejxxnndrrjrrrfufurururufjththjrjrjdjjjrj\u\ujrjeejrjjjj carbon

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victus00 [196]

Answer:

Got what wrong? A question?

5 0
3 years ago
Human blood consists of blood groups A, B, and O. However, there is one more blood group, AB, which contains alleles A and B in
algol13
It is codominant inheritance because, if the placement of the A and B molecules on each cell is controlled by the proteins that are coded by different versions of the same gene, then <span>IA and IB </span><span>are codominant but both are dominant to I<span>o</span>. If a person receives an <span>IA </span>allele and a <span>IB</span> allele, their blood type is type AB, in which characteristics of both A and B antigens are expressed.
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6 0
3 years ago
Read 2 more answers
How many bromine atoms are present in 37.9 g of CH2Br2?
VARVARA [1.3K]

Answer:

The answer to your question is: 6.55 x 10 ²³ atoms of Br

Explanation:

CH2Br2 = 37.9 g

MW CH2Br2 = (12 x 1) + (2 x 1) + (80 x 2) = 174 g

                   174 g of CH2Br2 ------------------  160 g of Br2

                   37.9 g of CH2Br2   ---------------     x

                x = 37.9 x 160/174 = 34.85 g of Br

                      1 mol of Br -----------------   160 g Br2

                         x              ----------------    174 g Be2

               x = 174 x 1 /160 = 1.088 mol of Br2

                1 mol of Br -----------------  6.023 x 10 ²³ atoms

            1.088 mol of Br -------------    x

                    x = 1.088 x 6.023 x 10 ²³ / 1 = 6.55 x 10 ²³ atoms

4 0
3 years ago
WILL GIVE BRAINLIEST ANSWER
OleMash [197]
The correct Answer based on my calculations is C
7 0
3 years ago
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When a caterpillar is big enough, it will form a chrysalis. During which stage of metamorphosis does this occur? (2 points) a Ad
weqwewe [10]

Answer: The stage of metamorphosis this occurs is called the PUPA stage. The correct option is D.

Explanation:

Metamorphosis can be defined as the change in form, mode of life and behaviour that occurs during embryonic development of an organism. In the metamorphosis of insects, which mostly reproduce sexually, insects can be grouped according to the way the eggs develop into adults. Some show:

--> Complete metamorphosis or

--> Incomplete metamorphosis.

In the life cycle of a butterfly, a COMPLETE metamorphosis occurs. This is because after fertilization, the EGG hatches into LARVA which passes through a PUPAL stage before becoming transformed into an ADULT insect. That is:

Egg --> Larva --> Pupa --> Imago.

When the caterpillar, which is the Larva stage, has reached its full size, it spins a pad of silk on a twig. It moves upward and attached it's clasper to this pad. It spin another silk thread at the thorax. These aids it to assume a slanting position with the head end pointing upwards. The pupa stage called the CHRYSALIS is reached when it tucks it's head under its thorax, arches it's body, shortens and broadens, and moults for the last time. Therefore the correct option is D (pupa).

6 0
3 years ago
Read 2 more answers
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