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Harrizon [31]
2 years ago
13

A 13.00 g sample of citric acid reacts with an excess of baking soda as shown in the equation.

Chemistry
2 answers:
UNO [17]2 years ago
8 0
From Law of definite proportion
You can compare this
Citric acid (Mw) / 3CO2 (Mw) = Citric acid (g) / 3CO2 (g)
So (12)6+(1)8+(16)7 / 3[12 + (16)2] = 13 / 3CO2
192 / 132 = 13 / CO2
You can get 3CO2 = 8.93 g
PolarNik [594]2 years ago
4 0

Answer:

eheheehehehszndn!jejxxnndrrjrrrfufurururufjththjrjrjdjjjrj\u\ujrjeejrjjjj carbon

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2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) (balanced)
Triss [41]

Answer:

Percent yield = 65.2 %

Explanation:

The reaction determines this:

2 moles of Al react to 3 moles of chlorine gas in order to produce 2 mol of aluminum chloride.

We determine the moles of chlorine:

52 g . 1mol /70.9g = 0.733 moles of Cl₂

3 moles of gas can produce 2 moles of salt

Then, our 0.733 moles may produce (0.733 . 2) / 3 = 0.489 moles of AlCl₃

We convert moles to mass to predict the 100 % yield

0.489 mol . 133.3 g /mol = 65.19 g

Percent yield = (Yield produced / 100 % yield) . 100

Percent yield = (42.5 g / 65.19g) . 100 = 65.2 %

3 0
3 years ago
How many grams are in 3.7 moles of Na2O?
Arte-miy333 [17]

Answer:

mass = moles x molar mass

m= 3.7 x (23x2+16)

m= 3.7x62

m= 229.4g

7 0
3 years ago
Read 2 more answers
True or false? Steel is a chemical element.
Irina-Kira [14]
I think answer is false
8 0
3 years ago
Read 2 more answers
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
pogonyaev

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

5 0
3 years ago
Part B
sashaice [31]

The anticodons corresponding to the codons on the mRNA (from part A) is 5' CGA - AAA - GUU 3'.

<h3>What are anticodons?</h3>

Anticodons are nucleotide sequences on tRNA molecules that are complementary to the codons found on mRNA molecules.

The anticodons on tRNA molecules determine the amino acid that is carried by the tRNA.

Just like codons, anticodons occur in triplets of nucleotide sequences.

Considering the codons on the mRNA molecule:

3’ GCT | TTT | CAA | AAA ’5

The complementary anticodon will be:

5' CGA - AAA - GUU 3'

Learn more about anticodons at:brainly.com/question/28067314

#SPJ1

7 0
1 year ago
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