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iren2701 [21]
4 years ago
15

An atom of calcium contains 20 protons how many electrons does it have

Chemistry
1 answer:
harina [27]4 years ago
4 0
20.

Atomic number is equivalent to its protons and electrons. :)
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Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left
Vera_Pavlovna [14]
So C12 is the limiting reactant and P4 is the excess
Mass P4 consumed= 0.31 mol X 123.9 g/mol =38.41 g P4 consumed.
Hope i helped
6 0
3 years ago
Please answer fast if can, will give Brainiest
Vilka [71]

From the absorption spectra of a gas, we can see the  amount of thermal energy the gas contains (option D).

<h3>What is the absorption spectra?</h3>

The absorption spectra shows us the energy that is taken in by a gas. We know that when a gas is heated, it absorbs energy which shows up in its absorption spectra.

Thus, from the absorption spectra of a gas, we can see the  amount of thermal energy the gas contains.

Learn more about absorption spectra:brainly.com/question/4239971

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7 0
2 years ago
What is an octet of electrons? Which elements contain an octet of electrons?
8090 [49]

Answer:

Explanation:

Octet, in chemistry, the eight-electron arrangement in the outer electron shell of the noble-gas atoms. This structure is held responsible for the relative inertness of the noble gases and the chemical behaviour of certain other elements.

5 0
3 years ago
Read 2 more answers
A student mixes a 10.0 ml sample of 1.0 m naoh(aq) with a 10.0 ml sample of 1.0 m hcl(aq) in a polystyrene container. the temper
AleksAgata [21]
Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
             = (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
5 0
3 years ago
If the half-life of Carbon-14 is 5700 years, how many years would it take a sample to decay from 1 gram to 31.3 mg
andrew-mc [135]

Answer:

28500 years

Explanation:

Applying,

A = A'(2^{x/y})............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313(2^{x/5700})

2^{x/5700} = 1/0.0313

2^{x/5700}  = 31.95

2^{x/5700} ≈ 32

2^{x/5700} ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

3 0
3 years ago
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