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Black_prince [1.1K]
3 years ago
15

1.) Which of the following is an example of using creativity while doing background research?

Chemistry
1 answer:
ioda3 years ago
5 0

1) Answer is: D. Writing a hypothesis.

The scientific method is a process for experimentation that is used to explore observations.

Steps of the scientific method:

1) ask a question about something that is observed.

2) do background research.

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested.

4) test of hypothesis.

5) analyze collected data and draw a conclusion.

2) Answer is: A. Carbon and oxygen are chemically bonded in it.

A compound (in this example carbon dioxide CO₂) is a pure substance because its molecule cannot be broken down into simpler particles by physical means.  

A chemical compound is a chemical substance composed of many identical molecules composed of atoms held together by chemical bonds.  

Carbon dioxide (CO₂) are inorganic compounds with covalent bonds between carbon and oxygen.

3) Answer is: B. Components that are mixed can be in different states of matter.

A single substance can be used to make a mixture if the substance is composed of more than one element is not correct, because mixture is composed of at least two substances. For example mixture of water and alcohol ethanol.

There is a definite recipe to make each mixture, so the composition of a mixture is set is not correct, because composition of mixture can vary.

Components that are mixed can be in different states of matter is correct, for example mixture of salt (solid) and water (liquid).

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For the reaction 2k(s)+br2(l)→2kbr(s) calculate how many grams of the product form when 21.4 g of br2 completely reacts. assume
Neko [114]
The balanced equation for the above reaction is as follows;
2K + Br₂ --> 2KBr 
Stoichiometry of Br₂ to KBr is 1:2
we have been told that K is present which means that Br₂ is the limiting reactant. Limiting reactant is the reactant that is fully consumed in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of Br moles reacted - 21.4 g / 160 g/mol = 0.134 mol
According to stoichiometry, 
1 mol of Br₂ forms 2 mol of KBr 
therefore 0.134 mol of Br₂ forms 2x0.134 = 0.268 mol of KBr
mass of KBr formed - 0.268 mol x 119 g/mol = 31.9 g of KBr
 a mass of 31.9 g of KBr is formed 
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