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Dovator [93]
3 years ago
11

Consider 70.0-g samples of two different compounds consisting of only sulfur and oxygen. One of the compounds consists of 35.0 g

of sulfur, and the other has 28.0 g of sulfur. Determine the ratio in whole numbers of the masses of sulfur that combine with 1.00 g of oxygen between the two compounds.
Chemistry
1 answer:
Mariana [72]3 years ago
5 0

Answer:

1 : 1.5

Explanation:

First Sample;

Ratio of sulfur and Oxygen

Mass of sulfur : Mass of oxygen

Mass of oxygen = Mass of sample - Mass of sulfur = 70 - 35 = 35g

35g : 35g

1 : 1

Second Sample;

Ratio of sulfur and Oxygen

Mass of sulfur : Mass of oxygen

Mass of oxygen = Mass of sample - Mass of sulfur = 70 - 28 = 42g

28g : 42g

1 : 1.5

Further reducing it to make oxygen 1;

0.6667 : 1

ratio in whole numbers of the masses of sulfur that combine with 1.00 g of oxygen between the two compounds;

0.6667 : 1

1 : 1.5

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Afina-wow [57]

Answer:

1.811 g

Explanation:

The computation of the mass need to use to make the solution is shown below:

We know that molarity is

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So,

Number\ of\ moles = Molarity\ \times Volume\ in\ L

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Now

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where,

The Molecular weight of NaCl is 58.44 g/mole

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So, the mass of NaCL is

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Answer:

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The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

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The relation between heat and molar heat of fusion is,

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Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

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Consider a possible triatomic molecule containing a nitrogen, oxygen, and fluorine atoms for the following questions.
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Answer:

a) nitrogen

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If we consider fluorine, oxygen and nitrogen; nitrogen is the least electronegative of the trio hence it should be the central atom of the triatomic molecule.

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