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Fittoniya [83]
3 years ago
9

How many atoms are in 5 GRAMS of Fe2O3

Chemistry
1 answer:
Llana [10]3 years ago
6 0

There are two iron atoms and three oxygen atoms in each molecule of Fe2O3. So that's five atoms per molecule.

One mole of any molecular substance contains <span>6.02×1023</span> molecules. Since there are two iron atoms in each of the molecules we're considering, there will be <span><span>(6.02×1023)</span>⋅2=1.204×1024</span> iron atoms in a whole mole of them.

But we're considering 0.550 mol, so multiply by 0.550:

<span>n=(0.550</span> mol<span>)⋅<span>(3.01×1024</span></span> atoms/mol<span>)=6.62×1023</span> iron atoms.

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alina1380 [7]
The solution for this problem is:
Let x = speed of wind

Speed of plane with the wind = x + 100

Speed of plane against the wind = 100 -x 

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3 years ago
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What is the empirical formula of a compound that contains 25.92 percent nitrogen and 74.07 percent oxygen?
pychu [463]

<span><span>N2</span><span>O5</span></span>

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When given %, assume you have 100 g of the substance. Find moles, divide by lowest count. In this case you'll end up with

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The ratio between these is <span>2.502 mol O/mol N</span>, which corresponds closely with <span><span>N2</span><span>O5</span></span>.

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5 pounds 2 ounces.

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