What would the weight of an astronaut be on Neptune if his mass is 68 kg and acceleration of gravity of Neptune is 11.15 m/s^2?

1 answer:

6 0

Weight = Mass of object * Gravity of experimented place
Here, m = 68 Kg
g' = 11.15 m/s²

Substitute their values,
w = 68 * 11.15
w = 758.2 N

In short, Your Answer would be 758.2 Newtons

Hope this helps!

You might be interested in

Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before the collision, puck 1 is going 8 m/s to the east and

Angelina_Jolie [31]

A. I think that’s the correct answer

5 0

3 years ago

Read 2 more answers

When a beta minus decay occurs in an unstable nucleus, what happens to the atomic number of the nucleus?The atomic number increa

vivado [14]

Answer:

The atomic number increases by 1.

Explanation:

The beta minus decay is a process in which a neutron decays into a proton, emitting an electron and an anti-neutrino:

$n \rightarrow p + e + \bar{\nu}$

If this process occurs inside an unstable nucleus, we notice that:

- a neutron is converted into a proton, therefore

- the number of neutrons decreases by 1 and the number of protons increases by 1

Keep in mind that the atomic number of a nucleus corresponds to the number of protons it contains: therefore, since this number increases by 1, then the atomic number increases by 1.

5 0

2 years ago

The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant af

NemiM [27]

(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.

(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.

The given parameters:

<em>Mass of the baseball, m = 0.14 kg</em>
<em>Initial velocity of the baseball, u = 45 m/s west (negative direction)</em>
<em>Final velocity of the baseball, v = 35 m/s east (positive direction)</em>
<em>Time of contact, t = 0.01 s</em>

The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:

$a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2$

The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;

$F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N$

Learn more about average force here: brainly.com/question/16200276

4 0

2 years ago

Automobile which is being towed at constant velocity up the incline using the cable at c. The automobile has a mass of 5 mg and

Simora [160]

The value of the normal reaction force will be 4.65 kN and 31.76 kN.

<h3>What is force?</h3>

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The normal force on the car is,Na= Nb =1 kN

The force of the cable on the car is,F=1 kN

The force of the gravity is,W=mg

The balancing equation of force;

$\rm N_A+N_B+F sin \theta_2 -mg cos \theta_2 =0 \\\\ \rm -Fcos \theta_2 +mg sin \theta_1 =0 \\\\ Fcos \theta_2 \times a -F sin \theta_2 \times b -mg cos \theta_1 \times c -mg sin \theta_1 \times e +N_B (c+d)=0 \\\\ N_A+N_B+F sin 30^0 - 5 \times 9.81 cos 30^0 =0 \\\\ -$

Putting the value further;

$\rm N_A+N_B+F sin 30^0 - 5 \times 9.81 cos 30^0 =0 \\\\ -F cos 30^0 + 9.81 sin 20^0 =0 \\\\ F cos 30^ 0 (0.6)-F sin30^0 (1.5)-(5 \times 10^6) \times 9.81 \times cos 20^0 (1)-(5)(9.81)sin 20^0 +N_B \times 1.75 =0$