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pantera1 [17]
4 years ago
15

Explain how do winds cause surface currents?

Physics
1 answer:
igor_vitrenko [27]4 years ago
8 0

Answer:

As wind or an ocean current moves, the Earth spins underneath it. ... The Coriolis effect bends the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere.

Explanation:

The Coriolis effect causes winds and currents to form circular patterns.

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Which only list metalloids
HACTEHA [7]

Answer: I think the answer <em><u>MIGHT</u></em> be: Boron, germanium, and tellurium....

Explanation:I know this cuz I had this question on my unit test and I had to look it up online....Hope this helps

I really hope you guys find this helpful and thx so much for rating :D

       pls say something in chat if you found this helpful

                                              UwU           ;-;

                                                         

7 0
3 years ago
In which of these media will mechanical waves travel the slowest in?
Aleks [24]

Answer:

E

Explanation:

it has more mass

5 0
3 years ago
Identify the labeled parts in the figure.
ad-work [718]

Answer:

Chemical symbols Al, O, H, O or a,c,f,h.

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5 0
3 years ago
Plz help, and no silly answers cuz i will report you
ale4655 [162]

Answer:

15.3 N

Explanation:

Force = mass x acceleration

= 2.55 kg x 6.00 m/s^2

= 15.3 kgm/s^2 = 15.3 N

7 0
3 years ago
A charge of 2.00 μC flows onto the plates of a capacitor when it is connected to a 12.0-V potential source. What is the minimum
uysha [10]

To develop this problem we will apply the concept of energy conservation. For which the work carried out must be equivalent to the potential energy stored on the capacitor. We will start by finding the capacitance to later be able to calculate the energy and therefore the work in the capacitor

C = \frac{Q}{V}

Here,

C = Capacitance

V = Potential difference between the plates

Q = Charge between the capacitor plates

At the same time the energy stored in the capacitor can be defined as,

U = \frac{1}{2} CV^2

We will start by finding the value of the capacitance, so we will have to,

C = \frac{2\mu C}{12.0V}

C = 0.166\mu F

Finally using the expression for the energy we have that,

U = \frac{1}{2} CV^2

U = \frac{1}{2} (0.166\muF)(12.0V)^2

U = 11.0*10^{-6} J

Therefore the minimum amount of work that must be done in charging this capacitor is 11.0*10^{-6} J

8 0
4 years ago
Read 2 more answers
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