Question

A metal sphere is launched with an initial velocity of 1.5 m/s as it leaves the ramp. the end of the ramp is 1.20 m above the floor. calculate the range of the sphere.

Answer 1

First, calculate the time it requires for the ball to reach the ground, given that its y-component is similar to that of the free-falling body through the equation,

                    d = 0.5gt²

Substituting the known values,

                  1.2 = 0.5(9.8 m/s²)(t²)

The value of t is equal to 1.56 seconds.

To calculate for the range of the given motion, we use the equation,
 
               R = (Hx)t

where R is the range, Hx is the horizontal component of the force, and t is the time. Substituting,
 
             R = (1.5 m/s)(1.56 s)
                  R = 2.34 m

Answer: 2.34 m