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4 years ago

6

Does rust have the same properties as iron?

1 answer:

spayn [35]4 years ago

6 0

Answer:

This is a chemical property. If iron does rust, this is a slow chemical change since rust is an iron oxide with different properties than iron metal.

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If a device uses mains electricity at 230v and has a 13a fuse in the plug wht is the maximmum power it can safley use?

Harman [31]

Answer:

2990W

Explanation:

Given parameters:

Voltage = 230V

Current = 13A

Unknown:

Maximum power it can safely use = ?

Solution:

To solve this problem;

Power = Current x Voltage

Power = 230 x 13 = 2990W

5 0

3 years ago

A machine can never be 100% efficient because some work is always lost due to .

klasskru [66]

Friction
Hope it helped

5 0

4 years ago

Read 2 more answers

Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls

Dmitrij [34]

Answer:

$(a) 189.23 N$ , $(b) 47.31 N$ and $(c) 141.92 N$ .

Explanation:

Three balls are shown in figure having charge $q=1.45 \mu C$ . The middle ball, $B$ , is positively charged having charge $+q$ , and the remaining two outside balls, $A$ and $C$ , are negatively charged having charged $-q$ as shown.

$AC=20 cm$ and $AB=BC=10$ cm as B is the mid-point of AC.

Let $d_1=AC=20\times 10^{-3}m$ and $d_2=AB=BC=10\times 10^{-3}m$

From Coulomb's law, the magnitude of the force, $F$ , between two point charges having magnitudes $q_1 \& q_2$ , separated by distance, $d$ , is

$F=\frac {1}{4\pi\epsilon_0}\frac {q_1q_2}{d^2}\;\cdots (i)$

where, $\epsilon_0$ is the permittivity of free space and

$\frac {1}{4\pi\epsilon_0}=9\times 10^9$ in SI units.

This force is repulsive for the same nature of charges and attractive for the different nature of charges.

Now, Using equations(i),

(a) The magnitude of attraction force between balls A and B is

$F_{AB}=F_{BC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_2)^2}$

$\Rightarrow F_{AB}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(10\times 10^{-3}\right)^2}$

$\Rightarrow F_{AB}=189.23 N$

(a) The magnitude of the repulsive force between balls A and C is

$F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}$

$\Rightarrow F_{AC}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(20\times 10^{-3}\right)^2}$

$\Rightarrow F_{AC}=47.31 N$

(c) The magnitude of the net force, $F_{net}$ , on the outside of the ball is,

$F_{net}=189.23-47.31 N$

$\Rightarrow F_{net}=141.92 N$

4 0

3 years ago

Which of the following best explains work?

Anna71 [15]

Answer:

<h2>Which of the following best explains work?</h2>

<h3><em>Work occurs when a force acts on an object and causes a displacement of that object</em><em>.</em><em>.</em></h3>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>u</em><em>.</em><em>.</em>

5 0

2 years ago

Read 2 more answers

A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slit

Tom [10]

1.97 E-7 m should be right. I took this a while ago.

6 0

3 years ago