A. Forced vibrations, such as those between a tuning fork and a large cabinet surface, result in a much lower sound than was produced by the original vibrating body.
This equation is one of the most useful in classical physics. It is a concise statement of Isaac Newton's<span> Second Law of Motion, holding both the proportions and vectors of the Second Law. It translates as: The net force on an object is </span>equal<span> to the </span>mass<span>of the object multiplied by the </span>acceleration<span> of the object.</span>
Given: Heat Qout means useful work = 2800 J
Heat Qin = 8900 J
Required; Efficiency = ?
Formula: Efficiency = Qout/Qin = x 100%
= 2800 J/8900 J = 0.3146 X 100 %
Efficiency = 31.46%
Answer:
M = ρ V = 9 gm/cm^ 3 * cm^3 = 27 gm
a = (V2 - V1) / t = (6 - 2) m/s / 12 s = 1/3 m/s^2 the acceleration
F = M a = 27 gm * 1/3 m/s^2 = 9 dynes net force applied
The distance of the object from the lens is 3.12 cm.
<h3>What is magnification?</h3>
Magnification is the process of of enlarging an apparent size of an object.
<h3>Object distance</h3>
The object distance is calculated using the following lens formula;

where;
- M is the magnification
- V is the image distance
- U is object distance

Thus, the distance of the object from the lens is 3.12 cm.
Learn more about object distance here: brainly.com/question/24894435