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4 years ago

12

What are inside of cars so hot when left in the sun

2 answers:

Naya [18.7K]4 years ago

8 0

Answer:

metalllll/material

Explanation:

you know how dark shirts absorb the sun heat well its practically the same just with material.

"Why is the inside of a car so hot after sitting in the sun?

Cars warm up in the sun due to the greenhouse effect: Sunlight passing through the windows into the car is mostly absorbed by interior surfaces, then radiated back to the air as heat. ... “As a consequence, the inside of the car will warm because radiation is coming in but not much is going back out.”Jul 27, 2009

Curiosities: Does a dark-colored car heat up more in the sun than a ..."

Alchen [17]4 years ago

8 0

^^ Also is caused by something called the Greenhouse effect which causes ultra violet rays to come in and be reflected with infrared rays which get trapped and therefore cause heat for the car to be hot since infrared radiation is another word for heat

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3 years ago

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Solve and show work. How many grams of potassium permanganate, KMnO4 are need to make 1.25 L of 0.75 M solution?

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3 years ago

Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 8.97×10−3. Express your answer to thr

puteri [66]

Answer: The standard cell potential (E∘) for the reaction $X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)$ is -0.121 V

Explanation:

The reaction is:

$X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

where,

$\Delta G^o$ = Standard Gibbs free energy = ?

R = Gas constant = $8.314J/K mol$

T = temperature = 298 K

K= equilibrium constant = $8.97\times 10^{-3}$

Putting values in above equation, we get:

$\Delta G^0=-(8.314J/Kmol\times 298K\times \ln (8.97\times 10^{-3})\\\\\Delta G^0=11678.9J/mol$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 1

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = ?

Putting values in above equation, we get:

$11678.9J/mol=-1\times 96500\times E^0_{cell}$

$\frac{11678.9J/mol}{-96500}=E^0_{cell}$

$-0.121V=E^0_{cell}$

Thus standard cell potential (E∘) for the reaction $X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)$ is -0.121 V

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3 years ago

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Answer:

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3 years ago