Simplify <img src="https://tex.z-dn.net/?f=5%20%7B%20%7D%5E%7B2%7D%20%20-%204%20%7B%7D%5E%7B2%7D%20%20%3D%20" id="TexFormula

Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)

Yuki888 [10]

Answer:

656.3844

Step-by-step explanation:

Area of squares = $s^{2}$

s = measure of a side, all sides are the same.

$25.62^{2}$ use a calculator

3 0

2 years ago

Complete the sentence. 7 is 35% of ________

nataly862011 [7]

7 is 35% of x.

Thus, since 35% = 35/100,

35% of x is 7, so 35/100 * x = 7.

35x/100 = 7

35x=700

x = 20
7 is 35% of 20.

4 0

3 years ago

Read 2 more answers

What is 579 divided by 3

KonstantinChe [14]

Just so you know, you can always use a calculator... or google which I know you have access to, considering you are on this site. Well, actually you could be using the brainly app but that's not the point. What I am trying to say is... you don't have to waste your points on questions like this! That's what Google is for :) Btw... your answer is 193

Download odt

3 0

3 years ago

evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha

dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

a

The Fermi function for the energy KT is $F(E_o) = 0.2689$

b

The temperature is $T_k = 1261 \ K$

Step-by-step explanation:

From the question we are told that

The energy considered is $E = 0.5 eV$

Generally the Fermi function is mathematically represented as

$F(E_o) = \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }$

Here K is the Boltzmann constant with value $k = 1.380649 *10^{-23} J/K$

$E_F$ is the Fermi energy

$E_o$ is the initial energy level which is mathematically represented as

$E_o = E_F + KT$

So

$F(E_o) = \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{\frac{KT}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{ 1 } + 1}$

=> $F(E_o) = 0.2689$

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the Fermi function as

$F(E_k) = \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 } = 0.01$