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3 years ago

The half-life of a certain element is 100 days. How many half-lives will it be before only one-fourth of this element remains? 4

Chemistry

2 answers:

Georgia [21]3 years ago

7 0

The answer is 2 half lives, i checked

jolli1 [7]3 years ago

4 0

Answer;

2 half lives

Explanation;

-Half life is the time taken by a radioactive isotope to decay to half of the original amount.

-For example; if the original mass is 100% the time it takes to decay to 50% is the half life.

-Therefore, in our case; for the element to decay from 1 whole to a half of the element, is one half life, then decaying from a half to one-fourth of the element will be another half life, which means there are two half lives for an element to decay to one-fourth of the element.

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What is the difference between a solid and a gas

dem82 [27]

Answer:

Gas is for example oxygen or the air we breath and liquid is water.

Explanation:

6 0

3 years ago

Read 2 more answers

The white tern is a seabird that catches fish by plunging into the water. What physical features of the bird likely make this fe

V125BC [204]

White tern catches fish including crustaceans, flying fish, squid, and others. Prior of plunging into water, it hovers initially over the water surface and then either dives or dips in the surface, without getting entirely submerged into water, and catches its target.

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7 0

3 years ago

Kc for the reaction of hydrogen and iodine to produce hydrogen iodide.

tatiyna

Answer:

$[H_2]_{eq}=0.183M$

$[I_2]_{eq}=0.183M$

$[HI]_{eq}=0.025M$

Explanation:

Hello.

In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:

$2HI\rightleftharpoons H_2+I_2$

Whereas the law of mass action (equilibrium expression) is:

$Kc=\frac{[H_2][I_2]}{[HI]^2}$

That in terms of initial concentrations and reaction extent or change $x$ turns out:

$Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}$

And the solution via solver or quadratic equation is:

$x_1=0.183M\\\\x_2=0.210M$

Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:

$[H_2]_{eq}=0.183M$

$[I_2]_{eq}=0.183M$

$[HI]_{eq}=0.391M-2*0.183M=0.025M$

Regards.

6 0

3 years ago

How many grams of hcl is dissolved in 500 ml of a 0.2 m hcl solution?

umka21 [38]

It well be 9025 because it will dissolve in 0.8 hcl soluiton

7 0

3 years ago

What’s the answer?????

marin [14]

potential energy

kinetic energy

kinetic energy

idk last sorry =(

3 0

3 years ago