All categories

2 years ago

Calculate in gramm the mass of 0.1 mole of hydrochloric acid(h=1 ,cl=35.5)

Chemistry

1 answer:

babunello [35]2 years ago

6 0

Answer:

mass of HCl = 3.65 g

Explanation:

Data Given:

Moles of hydrochloric acid HCl = 0.1 mole

Mass in grams of hydrochloric acid HCl = ?

Solution:

Mole Formula

no. of moles = Mass in grams / molar mass

To find Mass in grams rearrange the above Formula

Mass in grams = no. of moles x molar mass . . . . . . . (1)

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Put values in equation 1

Mass in grams = 0.1 mole x 36.5 g/mol

Mass in grams = 3.65 g

mass of HCl = 3.65 g

You might be interested in

How are alpha, beta and gamma radiation characterized in terms of mass and charge?

Anarel [89]

Beta radiation - negative charge and the mass of an electron
Gamma radiation- no mass and no charge
Alpha radiation- He 4+/2

7 0

2 years ago

How can you determine if covalent bonding will occur?

Crank

If two nonmetals are bonded together. So look at your periodic table of elements and decide if the two elements that are being bonded are nonmetals or not.

5 0

3 years ago

Fluorine gas is placed in contact with calcium metal at high temperatures to produce calcium fluoride powder. What is the

Ira Lisetskai [31]

Answer: B aka #2

Explanation:

3 0

2 years ago

PLZ HURRY

Oxana [17]

Answer:

Explanation:

3 0

2 years ago

Read 2 more answers

A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k

Sergeeva-Olga [200]

<u>Answer:</u> The partial pressure of oxygen gas is 2.76 bar

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0831\text{ L bar }mol^{-1}K^{-1}$

n = Total number of moles = ?

Putting values in above equation, we get:

$5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol$

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ........(1)

where,

$p_A$ = partial pressure of carbon dioxide = 0.318 bar

$p_T$ = total pressure = 5.57 bar

$\chi_A$ = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

$0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, $\chi_{N_2}=\frac{0.221}{0.493}=0.448$

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

$p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar$

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0

3 years ago

Calculate in gramm the mass of 0.1 mole of hydrochloric acid(h=1 ,cl=35.5)​

Calculate in gramm the mass of 0.1 mole of hydrochloric acid(h=1 ,cl=35.5)