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Evgen [1.6K]
3 years ago
9

The crowd in a stadium creates a wave traveling across the stands by having people stand up and then sit down one after another.

The people move up and down creating the appearance of a wave moving across the stadium. This type of wave is best described as a) transverse wave b) compression wave c) elliptical wave d) electromagnetic wave
Physics
2 answers:
sergiy2304 [10]3 years ago
6 0
<span>The correct option is: (A) Transverse Wave

Explanation:
Transverse wave is a wave in which the medium vibrates at right angles to the direction of its propagation.

In this case, consider the crowd as the medium and the perceived motion of the wave as the propagation. When the crowd moves up and down, the perceived wave be either from left to right or right to left. In either case, the crowd movement is perpendicular to the propagation of the wave. Imagine the crowd's up-down movement along y-axis and the perceived propagation of the wave along x-axis. Both axes are perpendicular to each other. Hence, the correct option is (A) Transverse wave.</span>
Vitek1552 [10]3 years ago
5 0

Any part of the electromagnetic spectrum is a transverse wave.

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PART b)

Since we know that sum of kinetic energy and potential energy is constant here

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So here speed is maximum at the nearest point

Part C)

since gravitational potential energy inversely varies with distance so it's graph will be like hyperbolic graph with distance

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3 years ago
A ball is projected upward at time t=0.0s, from a point on a roof 90m above the ground. The ball rises, then falls and strikes t
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3 years ago
What have psychologists learned about perception from optical illusions ?
ruslelena [56]

Answer:

Explanation:

That an optical illusion somehow interferes with the way we see things. Even simple illusions can completely fool us. If you search out the term, you'll see all kinds of them.

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Read 2 more answers
1. explain why mid-sized cars and SUVs have different rollover fatality rates.
iris [78.8K]

Answer:

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2. Mid-sized cars and SUVs both have a fixed object fatality rate of 2.6/BVM. This is most likely because they have a similar mass and inertia. The force of the crash is likely to have about the same deceleration in both vehicles.

Explanation:

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8 0
3 years ago
Two boats leave the same port at the same time, with boat A traveling north at 15 knots (nautical miles per hour) and boat B tra
Mrrafil [7]

Answer:

The chance in distance is 25 knots

Explanation:

The distance between the two particles is given by:

s^2 = (x_A - x_B)^2+(y_A - y_B)^2  (1)

Since A is traveling north and B is traveling east we can say that their displacement vector are perpendicular and therefore (1) transformed as:

s^2 = x_B^2+y_A^2 (2)

Taking the differential with respect to time:

\displaystyle{2s\frac{ds}{dt}= 2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt}}  (3)

where \displaystyle{\frac{dx_B}{dt}}=v_B and \displaystyle{\frac{dx_A}{dt}}=v_A are the respective given velocities of the boats. To find s and x_B we make use of the given position for A, y_A=30, the Pythagoras theorem and the relation between distance and velocity for a movement with constant velocity.

\displaystyle{y_A = v_A\cdot t\rightarrow t = \frac{y_A}{v_A}=\frac{30}{15}=2 h

with this time, we know can now calculate the distance at which B is:

\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

and applying Pythagoras:

\displaystyle{s = \sqrt{x_B^2+y_A^2}=\sqrt{30^2 + 40^2}=\sqrt{2500}=50}

Now substituting all the values in (3) and solving for  \displaystyle{\frac{ds}{dt} } we get:

\displaystyle{\frac{ds}{dt} = \frac{1}{2s}(2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt})}\\\displaystyle{\frac{ds}{dt} = 25 \ knots}

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3 years ago
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