If 40.0 g of water at 70.0°c is mixed with 40.0 g of ethanol at 10.0°c, what is the final temperature of the mixture?
1 answer:
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8.1moles
Explanation:
Given parameters:
Mass of water to be decomposed = 29.2g
Unknown:
Number of moles of oxygen.
Solution:
To solve this problem, we first write the balanced reaction equation :
2H₂O → 2H₂ + O₂
Now convert the given mass of the water to number of moles;
Number of moles of water =
Molar mass of water = 2(1) + 16 = 18g/mol
Number of moles of water = = 16.2moles
From the balanced reaction equation:
2 moles of water produced 1 mole of oxygen gas;
16.2 mole of water will produce = 8.1moles of oxygen gas
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<u>Answer:</u> The outermost valence electron enters the p orbital.
<u>Explanation:</u>
Valence electrons are defined as the electrons which are present in outer most orbital of an atom.
Sulfur is the 16th element of the periodic table having 16 electrons.
Electronic configuration of sulfur atom is
The number of valence electrons are 2 + 4 = 6
These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.
Hence, the outermost valence electron enters p orbital.