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nadya68 [22]
3 years ago
13

How can a magnetic field be produced, using a wire, a battery, and and a nail?

Physics
2 answers:
Aleks [24]3 years ago
5 0
It is fairly easy to build an electromagnet. All you need to do is wrap some insulated copper wire around an iron core. If you attach a battery to the wire, an electric current will begin to flow and the iron core will become magnetized. When the battery is disconnected, the iron core will lose its magnetism. Follow these steps.
Step 1 - Gather the Materials
One iron nail fifteen centimeters (6 in) long
Three meters (10 ft) of 22 gauge insulated, stranded copper wire
One or more D-cell batteries
Step 2 - Remove some Insulation
Step 3 - Wrap the Wire Around the Nail
Step 4 - Connect the Battery
Darina [25.2K]3 years ago
4 0
<h2>Answer:</h2>

By wrapping wire around the nail and attaching battery to the wire ends

<h2>Explanation:</h2>

We can use a pair of wire cutter to remove a few centimeters of insulation from each end of the wire that is used. Then neatly wrapping the wire around the nail. The more wire we wrap around the nail, the stronger our electromagnet will be. After that attaching the battery to the ends of the wire will turn the coil into an electromagnet.


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Sasha has just gotten a new job in a nearby city. After comparison shopping, she found that renting a nice two-bedroom apartment
tatyana61 [14]

Ill provide the answer choices here, assuming its from edge.

A) Sasha’s monthly expenses would be less for buying than for renting.


B) The extra expenses in the mortgage payment cover all maintenance and repairs.


C) Sasha’s down payment will likely be less if she decided to buy.


D) Sasha will own the house and earn equity as its value increases.

the correct answer is D) Sasha will own the house and earn equity as its value increases.

6 0
3 years ago
Read 2 more answers
The temperature of a black body is 500 and its radiation is of wavelength 600 . If the number of oscillators with energy is 100
stiks02 [169]

Answer: An equation is missing in your question below is the missing equation

a) ≈ 8396

b) 150 nm/k

Explanation:

<u>A) Determine the number of Oscillators in the black body</u>

number of oscillators = 8395

attached below is the detailed solution

<u>b) determine the peak wavelength of the black body </u>

Black body temperature = 20,000 K

applying Wien's law / formula

λmax = b / T  ------ ( 1 )

T = 20,000 K

b = 3 * 10^6 nm

∴  λmax = 150 nm/k

4 0
2 years ago
What force holds the earth-moon system together?
Verdich [7]
Gravity holds the system together
7 0
3 years ago
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The flywheel is rotating with an angular velocity ω0 = 2.37 rad/s at time t = 0 when a torque is applied to increase its angular
nika2105 [10]

Answer:

ω = 12.023 rad/s

α = 222.61 rad/s²

Explanation:

We are given;

ω0 = 2.37 rad/s, t = 0 sec

ω =?, t = 0.22 sec

α =?

θ = 57°

From formulas,

Tangential acceleration; a_t = rα

Normal acceleration; a_n = rω²

tan θ = a_t/a_n

Thus; tan θ = rα/rω² = α/ω²

tan θ = α/ω²

α = ω²tan θ

Now, α = dω/dt

So; dω/dt = ω²tan θ

Rearranging, we have;

dω/ω² = dt × tan θ

Integrating both sides, we have;

(ω, ω0)∫dω/ω² = (t, 0)∫dt × tan θ

This gives;

-1[(1/ω_o) - (1/ω)] = t(tan θ)

Thus;

ω = ω_o/(1 - (ω_o × t × tan θ))

While;

α = dω/dt = ((ω_o)²×tan θ)/(1 - (ω_o × t × tan θ))²

Thus, plugging in the relevant values;

ω = 2.37/(1 - (2.37 × 0.22 × tan 57))

ω = 12.023 rad/s

Also;

α = (2.37² × tan 57)/(1 - (2.37 × 0.22 × tan 57))²

α = 8.64926751525/0.03885408979 = 222.61 rad/s²

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3 years ago
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lisov135 [29]

Answer:

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